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Solnce55 [7]
3 years ago
5

A projectile is fired straight upward with an initial veloc- ity of 100 m=s from the top of a building 20 m high and falls to th

e ground at the base of the building. Find (a) its maximum height above the ground; (b) when it passes the top of the building; (c) its total time in the air.
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

The answer to your question is:

a) h max = 529.7 m

b) t = 20.4 s

c) t = 20.6 s

Explanation:

a) h max = -(vo)² / 2g

              = 100² / 2(9.81)

              = 10000 / 19.62

              = 509.7 m

total height = 509.7 + 20 = 529.7 m

b)  

    h = gt² / 2

    t = √ 2h / g

    t = √ 2(509.7)/9.81

    t = √ 103.91

    t = 10.19 s  

    total time = 2 x t = 2 x 10.19 = 20.4 s

c)

   h = vot + 1/2gt²

   20 = 100t + 1/2(9.91) t²

  4.9t² + 100 t -20 = 0   quadratic equation

t = 0.19 s

Total time = 0.19 + 20.4 = 20.6 s

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Pls don't mind my writing. hope this helps you tho

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3 years ago
A solid cylinder of mass 12.0 kgkg and radius 0.250 mm is free to rotate without friction around its central axis. If you do 75.
dybincka [34]

Answer:

The final angular velocity is 20rad/s

Explanation:

We are given;

mass, m = 12 kg

radius, r = 0.25 m

Work done;W = 75 J

Moment of inertia of cylinder, I = (1/2) mr²

Thus,

I = (1/2) x 12 x 0.25² = 0.375 kg.m²

Now, from work energy theorem,

Work done = Change in kinetic energy

So, W = KE_f - KE_i

Now, Initial Kinetic Energy (KE_i) = 0

Final Kinetic Energy; KE_f = (1/2)Iω²

So, KE_f = (1/2) x 0.375 x ω²

KE_f = 0.1875 ω²

Now, W = 75 J

Thus,

From, W = KE_f - KE_i, we have;

75 = 0.1875 ω² - 0

75 = 0.1875 ω²

ω² = 75/0.1875

ω² = 400

ω = √400

ω = 20 rad/s

5 0
3 years ago
A long, thin straight wire with linear charge density ? runs down the center of a thin, hollow metal cylinder of radius R. The c
MaRussiya [10]

Answer:

a. E = \frac{\lambda }{(2\epsilon * r) }

b. E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

Explanation:

The important thing to remember is to use Gauss Law. This is a relation that describes the distribution of electric charge to the resultant electric field.

Linear charge density means charge per unit length of material.

Data:

The metal cylinder is hollow.

The unit length is L.

a.The expression will be as follows:

for charge inside the cylinder, where r < R, the expression is:

E = \frac{\lambda }{(2\epsilon * r) }

b. Let's assume that the cylinder is a coaxial cylinder with a radius r > R, then the electrical field strength is given as:

E = \frac{Q ( enclosed)}{A*\epsilon }

E = \frac{\lambda*L+2(\lambda)*L }{(A)*\epsilon(outside) }

E  = \frac{3(\lambda)L }{(2\pi*R*L*\epsilon(outside)  }

This gives:

E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

The solution informs us that there is a surface change taking place on the cylinder. Therefore, there will not be a magnetic field across it.

3 0
4 years ago
When testing a laptop power connector, how close should the voltage measured be to the accepted voltage of the laptop?
elixir [45]
When testing a laptop power connector, the voltage measured has be close to +/- 5% to the accepted voltage of the laptop. This is to ensure that the power connector would not pose any hazard to the user and is safe for use. So, for instance the accepted voltage is 19 V, when you test the power connector it should be that the reading is between 18 V to 20 V. Any reading below or above that range is not recommended for use. You can locate the accepted voltage on the battery or the laptop itself. To test a power connector, you can use a volt meter or a multi meter.
4 0
4 years ago
What is the acceleration of a 150 kg object pushed with a force of 1000 N?
kirill115 [55]

Answer:

<h2>6.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1000}{150}   \\  =  6.66666..

We have the final answer as

<h3>6.67 m/s²</h3>

Hope this helps you

8 0
3 years ago
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