A projectile is fired straight upward with an initial veloc- ity of 100 m=s from the top of a building 20 m high and falls to th e ground at the base of the building. Find (a) its maximum height above the ground; (b) when it passes the top of the building; (c) its total time in the air.
1 answer:
Answer:
The answer to your question is:
a) h max = 529.7 m
b) t = 20.4 s
c) t = 20.6 s
Explanation:
a) h max = -(vo)² / 2g
= 100² / 2(9.81)
= 10000 / 19.62
= 509.7 m
total height = 509.7 + 20 = 529.7 m
b)
h = gt² / 2
t = √ 2h / g
t = √ 2(509.7)/9.81
t = √ 103.91
t = 10.19 s
total time = 2 x t = 2 x 10.19 = 20.4 s
c)
h = vot + 1/2gt²
20 = 100t + 1/2(9.91) t²
4.9t² + 100 t -20 = 0 quadratic equation
t = 0.19 s
Total time = 0.19 + 20.4 = 20.6 s
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