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brilliants [131]
3 years ago
7

Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov

erlap the crests of another wave? Question 25 options:
Positive interference
Destructive interference
Constructive interference
Standing interference
Overlapping interference
Question 26 (1 point) As demonstrated by the Doppler Effect, why does sound increase in pitch as a sound source approaches you?
Question 26 options:
The waves are farther apart because the object is moving toward you
The waves are closer together because the object is moving toward you
Objects vibrate slower when they move forward
The sound is louder as the source gets closer
Objects vibrate faster when they move forward
Physics
1 answer:
bulgar [2K]3 years ago
4 0

Question 25 Answer: Destructive interference occurs.

<span>Question 26Answer: The waves are closer together (as they move) because the object is moving toward you.</span>

<span />

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A stone with a mass m is dropped from an airplane that has a horizontal velocity v at a height h above a lake. If air resistance
seropon [69]

Answer: Option B. R = (1/2)gt^2

Explanation:

S = R (horizontal distance)

V^2 = 2gS

V^2 = 2gR

R = V^2 / 2g

But V = gt

R = (gt)^2 / 2g

R = (g^2 x t^2) / 2g

R = gt^2 / 2

But t^2 = 2h/g

R = ( g x 2h/g) / 2

R = h

But h = (1/2)gt^2

R = h = (1/2)gt^2

4 0
3 years ago
1. How much force is needed to accelerate a 66 kg skier<br> at 2 m/sec2?
Tju [1.3M]

Answer:

<h2>132 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 66 × 2

We have the final answer as

<h3>132 N</h3>

Hope this helps you

3 0
3 years ago
Please help me with this​
masha68 [24]

Answer:

>400N is needed to balance that lever

7 0
2 years ago
A car enters a horizontal, curved roadbed of radius 50 m. the coefficient of static friction between the tires and the roadbed i
UkoKoshka [18]
Previous results tell us the speed (v) is given in terms of the coefficient of friction (k) and the radius of the curve (r) as
  v = √(kgr)
  v = √(0.20·9.8 m/s²·50 m)
  = 7√2 m/s ≈ 9.90 m/s
6 0
3 years ago
Read 2 more answers
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
2 years ago
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