Answer: The electric repulsion between the two protons is stronger than the gravitational attraction.
Explanation: Please see the attachments below
Answer:
Electric potential = 0.00054 V
Explanation:
We are given;
Charge; q = 3 pC = 3 × 10^(-12) C
Radius; r = 2 cm = 0.02 m
Formula for the electric potential of this surface will be;
V = kqr
Where;
K is a constant = 9 × 10^(9) N⋅m²/C².
Thus;
V = 9 × 10^(9) × 3 × 10^(-12) × 0.02
V = 0.00054 V
According to my examination I have confirmed that I do NOT repeat do NOT know this .
Answer:
n= 16021.03 slaps
Explanation:
Using law of Energy conservation
E_{thermal}= Kinetic energy of hand
⇒
m_h= mass of the hand = 0.4 kg
v_h= velocity of the hand = 10 m/s
n= number of slaps
c= 4180 J/Kg °C
m= mass of chicken = 1 kg
Assuming all the energy of hand goes into chicken
Given Ti=0°C and T_f= 170 F= 76.66°C
Now putting the values in above equation to get n

n= 16021.03 slaps