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Scrat [10]
3 years ago
14

What is the formula for momentum? * p = m/v f = m x a f = m/s p = m x v

Physics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

momentum in a body can be calculated using

<em><u>Mome</u></em><em><u>ntum</u></em><em><u>=</u></em><em><u>Mass×</u></em><em><u>V</u></em><em><u>e</u></em><em><u>l</u></em><em><u>o</u></em><em><u>s</u></em><em><u>i</u></em><em><u>t</u></em><em><u>y</u></em><em><u> </u></em>

<em><u>i</u></em><em><u>e(</u></em><em><u>p</u></em><em><u>=</u></em><em><u>m×</u></em><em><u>v</u></em><em><u>)</u></em>

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Phase, color, and ductility are all examples of what type of property?
Mama L [17]
Physical properties.
7 0
3 years ago
A storage tank containing oil (SG=0.92) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of o
blagie [28]

Answer:

a-1 Graph is attached. The relation is linear.

a-2 The corresponding height for 68 kPa Pressure is 7.54 m

a-3 The corresponding weight for 68 kPa Pressure is 1394726kg

b The original height of the column is 5.98 m

Explanation:

Part a

a-1

The graph is attached with the solution. The relation is linear as indicated by the line.

a-2

By the equation

P=\rho \times g \times h

Here

  • P is the pressure which is given as 68 kPa.
  • ρ is the density of the oil whose SG is 0.92. It is calculated as

                                       \rho=S.G \times \rho_{water}\\\rho=0.92 \times 1000 kg/m^3\\\rho=920 kg/m^3\\

  • g is the gravitational constant whose value is 9.8 m/s^2
  • h is the height which is to be calculated

                                        P=\rho \times g \times h\\h=\frac{P}{\rho \times g}\\h=\frac{68 \times 10^3}{920 \times 9.8}\\h=7.54m

So the height of column is 7.54m

a-3

By the relation of volume and density

M=\rho \times V

Here

  • ρ is the density of the oil which is 920 kg/m^3
  • V is the volume of cylinder with diameter 16m calculated as follows

                             V=\pi r^2h\\V=3.14\times (8)^2 \times 7.54\\V=1515.23 m^3

Mass is given as

                             M=\rho \times V\\M=920 \times 1515.23\\M=1394726kg

So the mass of oil leading to 68kPa is 1394726kg

Part b

Pressure variation is given as

                            \Delta P=P_{obs}-P_{atm}\\\Delta P=115-101 kPa\\\Delta P=14 kPa\\

Now corrected pressure is as

P_c=P_g-\Delta P\\P_c=68-14 kPa\\P_c=54 kPa

Finding the value of height for this corrected pressure as

P_c=\rho \times g \times h\\h=\frac{P_c}{\rho \times g}\\h=\frac{54 \times 10^3}{920 \times 9.8}\\h=5.98m

The original height of column is 5.98m

4 0
4 years ago
Which road would exert the LEAST amount of friction on a car?
bearhunter [10]

Answer:

Icy roads

Explanation:

There is so little friction you slide on it way more than other roads. :)

6 0
3 years ago
Hold the paper up to a mirror so
Ne4ueva [31]

Answer:

The image of everything in front of the mirror is reflected backward, retracing the path it traveled to get there. Nothing is switching left to right or up-down. Instead, it's being inverted front to back. ... That reflection represents the photons of light, bouncing back in the same direction from which they came

Explanation:

5 0
3 years ago
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45. When you park on a level road next to a curb: A. Your wheels must be within 18 inches of the curb B. Your front wheels must
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Answer:

A

Explanation:

You must be within 18 inches.

4 0
3 years ago
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