Balanced equation :
1 CaCO3(s) = 1 CaO(s) + 1 CO2(g)
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Answer:
- <em><u>B) Bill's wagon is moving 4 times faster than Tom's. </u></em>
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Explanation:
The motion of the wagons is determined by the net force that acts upon them, according to Newton's second law of motion:
- Force = mass × acceleration ⇒ acceleration = Force / mass
From your data, you can fill this table to compare the accelerations:
Bill's wagon Tom's wagon
mass (lb) 10 20
force 2F F
acceleration 2F/10 F/20
Find the ratio between both accelarations:
- Bill's wagon acceleration / Tom's wagon acceleration
- (2F/10) / (F/20) = (2 × 20 / 10 ) = 4
Meaning that the acceleration of Bill's wagon is 4 times the acceleration of Tom's wagon.
Assuming, that both wagons start from rest, you can obtain the speeds from the kinematic equation for uniformly accelerated motion:
- Speed = acceleration × time, V = a × t.
Call the acceleration of Tom's wagon X, then the acceleration of Bill's wagon will be 4X.
So, depending on the time, using V = a × t, the speeds will vary:
t (s) 1 2 3 4
Speed Tom's wagon X 2X 3X 4X
Speed Bill's wagon 4X 8X 12X 16X
Concluding that Bill's wagon is moving 4 times faster than Tom's (option B).
5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.
The mass per unit amount of a certain chemical entity is known as the molar mass (symbol M, SI unit kgmol1). The chemical entity in question should always be identified in accordance with the mole definition.
The number of atoms present in 1 mole of hydrogen is equal to 6.02 × 10²³ known as Avogadro’s number (NA).
The units of molar mass follow its definition; grams per mole. Mathematically, the defining equation of molar mass is
Molar mass = mass/mole = g/mol
180g/mol glucose has = 6.02 × 10²³
x g/mol glucose has = 1.90 × 10 ²²
To find x;
x = 5.6 × 10⁻³ g/mol
Therefore, 5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.
Learn more about molar mass here:
brainly.com/question/837939
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Answer:
The answer is Graph A, because there is a direct relationship between pressure and volume.
The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure.
