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ryzh [129]
3 years ago
11

24) When first turning a jigsaw on, one should:

Engineering
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Simple Answer:

Always make sure you are using the right blade for the material. Make sure you put on safety goggles and use THICC gloves. DO NOT start cutting when children are around, as it is possible they may get hurt.

Answer:

"1

Plug in the saw or put in the battery pack. Once you have your saw blade secured, plug the cord into a nearby outlet so you can reach all the areas you need to cut. If you have a cordless jigsaw, insert the battery pack into the port on the back of the machine.[7]  

Whenever you aren’t using your jigsaw, unplug it so you don’t accidentally turn it

Coil the cord once around your dominant arm so the cord doesn’t hang down loosely.

2

Wear safety glasses and a dust mask. Before you make any cuts, cover your mouth and nose with a face mask so you don’t inhale any dust. Protect your eyes with safety glasses in case any of your material kicks back towards you.[8]  

3

Clamp your material to your work surface so it doesn’t move around. Make sure the area where you plan on making your cuts extends over the edge of your work surface. Use at least 2 C-clamps on the edge of your work surface to hold the material sturdy. If it still moves around easily, use additional clamps or rest a heavy object on the opposite end of the material.[9]  

If you need to cut a hole in the center of your material, balance it between 2 sawhorses so you can easily cut through it without damaging your work surface.

You don’t need to use clamps if you’re making a vertical cut on a wall."

<h2>-<em>How to Use a Jigsaw </em></h2><h2><em>Co-authored by WikiHow Staff | Reader-Approved | 19 References  </em></h2><h2><em>Updated: March 29, 2019</em></h2>

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The occupants of a remote village rely exclusively on a single micro hydro facility for all of their electricity needs. The hydr
nordsb [41]

Answer:

In summer the power available is 357.55 kW and in winter the power available is 59.59 kW

Explanation:

Given data:

height = 1500 ft = 457.2 m

30 gallon = 0.114 m³

5 gallon = 0.019 m³

In summer the power available is:

P=\mu \rho ghQ

Where

μ = efficiency = 0.7

ρ = density of water = 1000 kg/m³

g = gravity = 9.8 m/s²

Q = 0.114 m³

Replacing:

P=0.7*1000*9.8*457.2*0.114=3.575x10^{5} W=357.55kW

In winter the power available is

P=0.7*1000*9.8*457.2*0.019=59591.45W=59.59kW

6 0
3 years ago
More discussion about seriesConnect(Ohm) function In your main(), first, construct the first circuit object, called ckt1, using
STALIN [3.7K]

Answer:

resistor.h

//circuit class template

#ifndef TEST_H

#define TEST_H

#include<iostream>

#include<string>

#include<vector>

#include<cstdlib>

#include<ctime>

#include<cmath>

using namespace std;

//Node for a resistor

struct node {

  string name;

  double resistance;

  double voltage_across;

  double power_across;

};

//Create a class Ohms

class Ohms {

//Attributes of class

private:

  vector<node> resistors;

  double voltage;

  double current;

//Member functions

public:

  //Default constructor

  Ohms();

  //Parameterized constructor

  Ohms(double);

  //Mutator for volatage

  void setVoltage(double);

  //Set a resistance

  bool setOneResistance(string, double);

  //Accessor for voltage

  double getVoltage();

  //Accessor for current

  double getCurrent();

  //Accessor for a resistor

  vector<node> getNode();

  //Sum of resistance

  double sumResist();

  //Calculate current

  bool calcCurrent();

  //Calculate voltage across

  bool calcVoltageAcross();

  //Calculate power across

  bool calcPowerAcross();

  //Calculate total power

  double calcTotalPower();

  //Display total

  void displayTotal();

  //Series connect check

  bool seriesConnect(Ohms);

  //Series connect check

  bool seriesConnect(vector<Ohms>&);

  //Overload operator

  bool operator<(Ohms);

};

#endif // !TEST_H

resistor.cpp

//Implementation of resistor.h

#include "resistor.h"

//Default constructor,set voltage 0

Ohms::Ohms() {

  voltage = 0;

}

//Parameterized constructor, set voltage as passed voltage

Ohms::Ohms(double volt) {

  voltage = volt;

}

//Mutator for volatage,set voltage as passed voltage

void Ohms::setVoltage(double volt) {

  voltage = volt;

}

//Set a resistance

bool Ohms::setOneResistance(string name, double resistance) {

  if (resistance <= 0){

      return false;

  }

  node n;

  n.name = name;

  n.resistance = resistance;

  resistors.push_back(n);

  return true;

}

//Accessor for voltage

double Ohms::getVoltage() {

  return voltage;

}

//Accessor for current

double Ohms::getCurrent() {

  return current;

}

//Accessor for a resistor

vector<node> Ohms::getNode() {

  return resistors;

}

//Sum of resistance

double Ohms::sumResist() {

  double total = 0;

  for (int i = 0; i < resistors.size(); i++) {

      total += resistors[i].resistance;

  }

  return total;

}

//Calculate current

bool Ohms::calcCurrent() {

  if (voltage <= 0 || resistors.size() == 0) {

      return false;

  }

  current = voltage / sumResist();

  return true;

}

//Calculate voltage across

bool Ohms::calcVoltageAcross() {

  if (voltage <= 0 || resistors.size() == 0) {

      return false;

  }

  double voltAcross = 0;

  for (int i = 0; i < resistors.size(); i++) {

      voltAcross += resistors[i].voltage_across;

  }

  return true;

}

//Calculate power across

bool Ohms::calcPowerAcross() {

  if (voltage <= 0 || resistors.size() == 0) {

      return false;

  }

  double powerAcross = 0;

  for (int i = 0; i < resistors.size(); i++) {

      powerAcross += resistors[i].power_across;

  }

  return true;

}

//Calculate total power

double Ohms::calcTotalPower() {

  calcCurrent();

  return voltage * current;

}

//Display total

void Ohms::displayTotal() {

  for (int i = 0; i < resistors.size(); i++) {

      cout << "ResistorName: " << resistors[i].name << ", Resistance: " << resistors[i].resistance

          << ", Voltage_Across: " << resistors[i].voltage_across << ", Power_Across: " << resistors[i].power_across << endl;

  }

}

//Series connect check

bool Ohms::seriesConnect(Ohms ohms) {

  if (ohms.getNode().size() == 0) {

      return false;

  }

  vector<node> temp = ohms.getNode();

  for (int i = 0; i < temp.size(); i++) {

      this->resistors.push_back(temp[i]);

  }

  return true;

}

//Series connect check

bool Ohms::seriesConnect(vector<Ohms>&ohms) {

  if (ohms.size() == 0) {

      return false;

  }

  for (int i = 0; i < ohms.size(); i++) {

      this->seriesConnect(ohms[i]);

  }

  return true;

}

//Overload operator

bool Ohms::operator<(Ohms ohms) {

  if (ohms.getNode().size() == 0) {

      return false;

  }

  if (this->sumResist() < ohms.sumResist()) {

      return true;

  }

  return false;

}

main.cpp

#include "resistor.h"

int main()

{

   //Set circuit voltage

  Ohms ckt1(100);

  //Loop to set resistors in circuit

  int i = 0;

  string name;

  double resistance;

  while (i < 3) {

      cout << "Enter resistor name: ";

      cin >> name;

      cout << "Enter resistance of circuit: ";

      cin >> resistance;

      //Set one resistance

      ckt1.setOneResistance(name, resistance);

      cin.ignore();

      i++;

  }

  //calculate totalpower and power consumption

  cout << "Total power consumption = " << ckt1.calcTotalPower() << endl;

  return 0;

}

Output

Enter resistor name: R1

Enter resistance of circuit: 2.5

Enter resistor name: R2

Enter resistance of circuit: 1.6

Enter resistor name: R3

Enter resistance of circuit: 1.2

Total power consumption = 1886.79

Explanation:

Note

Please add all member function details.Its difficult to figure out what each function meant to be.

8 0
3 years ago
A(n) ___ is an electric device that uses electromagnetism to change (step up or step down) AC voltage from one level to another.
Pie

Answer:

A transformer is an electric device that uses electromagnetism to change voltage from one level to another or to isolate one voltage from another.

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3 years ago
Fixed objects that fix a location are called
Zielflug [23.3K]
Fix3d locationz i thinkz
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3 years ago
Consider the database table structure shown in the figure. (a) Write a SELECT statement statement (compatible with an Oracle RDB
Delicious77 [7]

Answer:

The table is attached as a picture.

a)

Select VENDOR_CONTACT_LAST_NAME || ', ' || VENDOR_CONTACT_FIRST_NAME "full_name" from VENDORS where VENDOR_CONTACT_LAST_NAME like 'A%' or VENDOR_CONTACT_LAST_NAME like 'E%' order by VENDOR_CONTACT_LAST_NAME,VENDOR_CONTACT_FIRST_NAME;

concatenation operator || is used . Also LIKE is used for pattern matching. full_name is alias for the concatenated column

b) As sample data is not given ,Please test the query for the data given in table

Explanation:

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