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Levart [38]
2 years ago
13

The Environmental Protection Agency (EPA) has standards and regulations that says that the lead level in soil cannot exceed the

limit of 400 parts per million (ppm) in public play areas designed for children. Mike is an inspector, and he takes 50 randomly selected soil samples from a site where they are considering building a playground.
These data show a sample mean of x = 390.25 ppm and standard deviation of Sx = 30.5 ppm. Answer the following:

1. Determine the critical t value and along with the confidence interval for 95% level of

confidence. 2. What does this interval suggest?
Engineering
1 answer:
DENIUS [597]2 years ago
3 0

Answer:

See below

Explanation:

<u>Check One-Sample T-Interval Conditions</u>

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

<u>One-Sample T-Interval Information</u>

  • Formula --> CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})
  • Sample Mean --> \bar{x}=390.25
  • Critical Value --> t^*=2.0096 (given df=n-1=50-1=49 degrees of freedom at a 95% confidence level)
  • Sample Size --> n=50
  • Sample Standard Deviation --> S_x=30.5

<u>Problem 1</u>

The critical t-value, as mentioned previously, would be t^*=2.0096, making the 95% confidence interval equal to CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

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Given a manhole with the outlet invert elevation of 2605. A run of 48 inch pipe connects to the next manhole at an invert elevat
alexdok [17]

Answer:

Distance between manholes = 166.67 (Unit) (Approx)

Explanation:

Given:

Invert elevation = 2605

New Invert elevation = 2610

Grade % = 3% = 0.03

Find:

Distance between manholes

Computation:

Grade % = (Change in elevation)/Distance between objects

0.03 = (2610-2605)/Distance between manholes

0.03 = 5 / Distance between manholes

Distance between manholes = 166.67 (Unit) (Approx)

5 0
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Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
Anastasy [175]

Answer:

If they can put all these together than what would the difference be between them

Explanation:

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3 years ago
Which of the following is most characteristic of OSHA's relationship with professional trade organizations in residential constr
geniusboy [140]

Answer:

its beneficial

Explanation:

took the test

3 0
3 years ago
Which of the following statements regarding piston rings is false? Select one: a.
sveta [45]

Compression ring prevents pressurized refrigerant from blowing past the piston into the crankcase is the false statement.

Answer: Option A

<u>Explanation:</u>

Compression rings seal the combustion chamber from crankcase and then transfer heat to the cylinder from the piston. The piston rings are present in an internal combustion engine or steam engine with multi functions. The functions of piston rings are,

  • Ensuring the combustion chamber is tightly sealed as to reduce the loss of gas to crankcase .
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3 0
4 years ago
A clay sample has a wet mass of 417 g, a volume of 276 cm3, and a specific gravity of 2.70. When oven dried, the mass becomes 22
nataly862011 [7]

Answer:

a. WATER CONTENT.

mass of water (MW)= 417g - 225g

Mw= 192g

M= (Mw / Ms)

M= [192/417]

M= 0.46

M= 46.0%

b. Void Ration (e)

To calculate the void ratio we must first calculate the volume of solids. Then we can find the volume of voids by subtracting the volume of solids from the total volume.

Ps= (Ms/Vs)=GsPw

Therefore

Vs= (Ms/GsPw)

Vs= (417/ 2.70*1000)

Vs= 0.154cm3

But V= Vv+Vs

Vv=V-Vs

e= (Vv/Vs)

8 0
3 years ago
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