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Julli [10]
3 years ago
6

Hydrogen is preferred for regeneratively cooled nozzles because it is easy to pump. a)-True b)-False

Engineering
1 answer:
Roman55 [17]3 years ago
6 0

Answer:

TRUE

Explanation: Hydrogen is preferred for regeneratively cooled nozzles because it is easy to pump. we all know that hydrogen is a very light gas so its pumping is very easy and for regeneratively cooled nozzles we need the gases which can be pumped very easily and hydrogen is very light so its pumping is easy and we can use it in regenratively cooled nozzles.

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Are we living in a simulation! <br> True <br> False
olchik [2.2K]
False

i would hope:):):)
4 0
3 years ago
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All circuit conductors between the service equipment, the source of a separately derived system, or other power supply source an
Zepler [3.9K]

Answer: Feeder

Explanation:

The National Electrical Code (NEC) which has been adopted by all 50 stated in the Repubic is a code that governs the installation of electrical devices, circuits and systems. The primary purpose is to safeguard the populace in the use of electricity which can prove to be hazardous if not properly used.

Article 100 of the the NEC  defines a Feeder as <em>All circuit conductors between the service equipment, the source of a separately derived system, or other power supply source and the final branch-circuit overcurrent device.</em>

6 0
3 years ago
An average person produce 0.25 kg of moisture while taking a shower and 0.05 kg while bathing in a tub. Consider a family of fou
Gre4nikov [31]

Answer:

Q = 2450 KJ/day

Explanation:

We are given;

The amount of moisture produced by a person while taking shower; m = 0.25 kg/person

Total number of persons in the family; N = 4

Latent heat of vaporization of water:

h_fg = 2450 KJ/kg

Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day

The formula for the amount of latent heat added to the space due to shower per day, is given as;

Q = m_total x h_fg

Plugging in the relevant values;

Q = 1 x 2450 = 2450 KJ/day

7 0
3 years ago
_______________ is an effective way to manage waste in a shop.
Murrr4er [49]

Answer:

To reduce waste.

Explanation:

3 0
3 years ago
The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
n200080 [17]

Answer:500,551.02

Explanation:

Given

Initial enthaly of pump \left ( h_1\right )=500KJ/kg

Final  enthaly of pump \left ( h_2\right )=550KJ/kg

Final  enthaly of pump when efficiency is 100%=h_2^{'}

Now pump efficiency is 98%

\eta=\frac{h_2-h_1}{h_2^{'}-h_1}

0.98=\frac{550-500}{h_2-500}

h_2=551.02KJ/kg

therefore initial and final enthalpy of pump for 100 % efficiency

initial=500KJ/kg

Final=551.02KJ/kg

3 0
3 years ago
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