Assume your line starts at zero, your first point is (-3,5) meaning your have a slope of 5/-3
[ f(x) = 5/-3x + b]
Answer:
Huh...? You said free points...
Step-by-step explanation:
Answer:
Step-by-step explanation:
∵ ABCD is a rhombus
∴ AC is ⊥ on BD
∴ ΔAEB is right angled triangle
24q^2 / 8q^-3
lets break this down...
24/8 = 3
q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5
put them together and u get : 3q^5
