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aleksandr82 [10.1K]
3 years ago
9

Which of the following materials is able to absorb large amounts of energy without changing temperature very much? air concrete

water soil
Physics
2 answers:
Sedbober [7]3 years ago
8 0

Answer: Water

The other person also has the correct answer, just paraphrasing.

Alinara [238K]3 years ago
6 0
At normal temperature, specific heat of air = 1.006 concrete =0.96 water =4.187 (all are in KJ/KgK) soil = 0.80 So, from <span>Q=mcDeltaT</span><span> higher the specific heat lower the change in temperature for same quantity of heat supplied. Therefore, water is the answer.</span>
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What is the electron configuration of this element? *for ne
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Answer:

[He]2s²2p⁶

Explanation:

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3 years ago
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Two small spheres with mass 10 gm and charge q, are suspended from a point by threads of length L=0.22m. What is the charge on e
Nataliya [291]

Answer:

q=1.95*10^{-7}C

Explanation:

According to the free-body diagram of the system, we have:

\sum F_y: Tcos(15^\circ)-mg=0(1)\\\sum F_x: Tsin(15^\circ)-F_e=0(2)

So, we can solve for T from (1):

T=\frac{mg}{cos(15^\circ)}(3)

Replacing (3) in (2):

(\frac{mg}{cos(15^\circ)})sin(15^\circ)=F_e

The electric force (F_e) is given by the Coulomb's law. Recall that the charge q is the same in both spheres:

(\frac{mg}{cos(15^\circ)})sin(15^\circ)=\frac{kq^2}{r^2}(4)

According to pythagoras theorem, the distance of separation (r) of the spheres are given by:

sin(15^\circ)=\frac{\frac{r}{2}}{L}\\r=2Lsin(15^\circ)(5)

Finally, we replace (5) in (4) and solving for q:

mgtan(15^\circ)=\frac{kq^2}{(2Lsin(15^\circ))^2}\\q=\sqrt{\frac{mgtan(15^\circ)(2Lsin(15^\circ))^2}{k}}\\q=\sqrt{\frac{10*10^{-3}kg(9.8\frac{m}{s^2})tan(15^\circ)(2(0.22m)sin(15^\circ))^2}{8.98*10^{9}\frac{N\cdot m^2}{C^2}}}\\q=1.95*10^{-7}C

5 0
3 years ago
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Brut [27]

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  B = 9.16 10⁻²  T

Explanation:

The speed selector is a configuration where the electric and magnetic force has the opposite direction, which for a specific speed cancel

       q v B = q E

       v = E / B

       B = E / v

Let's calculate

      B = 4.4 10⁵ / 4.8 10⁶

      B = 9.16 10⁻²  T

5 0
3 years ago
Two resistors are to be combined in parallelto form an equivalent resistance of 400Ω. The resistors are takenfrom available stoc
vivado [14]

Answer:

ΔR_{e} = 84   Ω,     R_{e} = (40 ± 8) 10¹   Ω

Explanation:

The formula for parallel equivalent resistance is

          1 / R_{e} = ∑ 1 / Ri

In our case we use a resistance of each

           R₁ = 500 ± 50  Ω

          R₂ = 2000 ± 5%

This percentage equals

        0.05 = ΔR₂ / R₂

        ΔR₂ = 0.05 R₂

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We write the resistance

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We apply the initial formula

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Let's look for the error  (uncertainly) of Re

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Let's look for the uncertainty of this equation

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The uncertainty of a sum is

      ΔR’= ΔR₁ + ΔR₂

We substitute the values

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     ΔR_{e} / 400 = 0.1 + 0.05 + 0.06

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Let's write the resistance value with the correct significant figures

    R_{e} = (40 ± 8) 10¹   Ω

6 0
3 years ago
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