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3 years ago

If the load on Pulley E is 20N, how much effort is needed to life it?

1 answer:

7 0

It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20

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In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a s

zepelin [54]

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

3 0

2 years ago

X-rays have so much energy they can go right through your ___ and ___.

Stolb23 [73]

Answer:

X-rays have so much energy they can go right through your <u>muscles</u> and <u>fat</u>.

Explanation:

There are actually more ways to fill in those two blanks... Different parts of the body absorb x-rays in varying degrees, but soft tissues (like skin, muscles, fat, and organs) allow most of the X-rays to pass through.

8 0

3 years ago

What is the fastest motion that can be measured in any frame of reference?

Furkat [3]

Answer: The answer is D: 300,000km/s

Explanation:

7 0

2 years ago

A box has a mass of 150kg and the surface area of the bottom of the box is :

charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

$pressure = \frac{force}{area} \\ = \frac{150 \times 10}{15} \\ = \frac{1500}{15} \\ = 100 pa$

3 0

3 years ago

For a given wave IF frequency doubles the wavelength

motikmotik

Answer:

C is halved

Explanation:

The frequency and the wavelength of a wave are related by the equation:

$v=f\lambda$

where

v is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

From the equation above, we see that for a given wave, if the wave is travelling in the same medium (and so, its speed is not changing), then the frequency and the wavelength are inversely proportional to each other.

Therefore, if the frequency doubles, the wavelength will halve in order to keep the speed constant:

$\lambda = \frac{v}{f}\\\lambda' = \frac{v}{f'}=\frac{v}{2f}=\frac{1}{2}(\frac{v}{f})=\frac{\lambda}{2}$

7 0

3 years ago