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Igoryamba
3 years ago
11

because the snow suddenly gets too slushy, you decide to carry your 100-newton sled the rest of the way home. How much workdo yo

u you do when you pick up your sled, lifting it 0.5meter upward? How much work do you do to carry the sled if your house is 800 meters away?
Physics
1 answer:
quester [9]3 years ago
3 0
When you lift it the work is 50 joules. When heading home the work is 80000joules
You might be interested in
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evablogger [386]

Answer:

b

Explanation:

3 0
3 years ago
Temperature change time base problem. Suppose V = 24 V, I = 0.1 A, for water: mw = 51 gm, cw = 4.18 J/gm ∘K-1, for resistor: mr
nirvana33 [79]

Answer:

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

I  = 0.1 ampere

mass of water mw = 51 gm

cr = 4.18 J/gm degree K^-1

mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

so equating both side we have

\frac{E}{t} = VI

solving for t

t = \frac{E}{VI}

t = \frac{m_w C_w \Delta T}{VI}

t = \frac{51 \times 4.18 \times (5 -0)}{24\times 0.1}

t = 444.125 sec

5 0
3 years ago
Read 2 more answers
a shell fired from a cannon at 60 ° from horizontal strikes a target 20m high at a distance 80m. Calculate the initial velocity
stich3 [128]

consider the motion along the X-direction

X = horizontal displacement = 80 m

V_{ox} = initial velocity along the x-direction = v Cos60

t = time of travel

using the equation

X = V_{ox}   t

80 = (v Cos60) (t)

t = 160/v                                         eq-1


consider the motion in vertical direction :

Y = vertical displacement = 20 m

V_{oy}  = initial velocity in Y-direction = v Sin60

a = acceleration = - 9.8 m/s²

t = time of travel = 160/v

using the equation

Y = V_{oy}  t + (0.5) a t²

20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²

v = 32.5 m/s

4 0
3 years ago
The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cr
tatyana61 [14]

Answer:

The ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

Explanation:

The resistance of the coil is directly proportional to the length of the coil and inversely proportional to the area of coil and hence inversely proportional to the square of radius of the coil.

So, the ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

8 0
3 years ago
Which of the following is a quantitative observation?
liubo4ka [24]

The statement that is a quantitative observation is that bird has four different colors on it (option B).

<h3>What is a quantitative research?</h3>

A quantitative research is a systematic scientific investigation of quantitative properties and phenomena and their relationships, using statistical methods.

A quantitative observation has to do with numbers or numeric analysis.

This suggests that the statement that is a quantitative observation is that bird has four different colors on it.

Learn more about quantitative observations at: brainly.com/question/1434538

#SPJ1

8 0
1 year ago
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