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cupoosta [38]
3 years ago
12

All numbers divisible by 25 are also divisible by 5 ?true or false

Physics
1 answer:
lara31 [8.8K]3 years ago
3 0
Yes 25 are also divisible by 5 because (5)(5) is 25 
Hope this helps
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Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s
34kurt

Answer:

T = 1.26 \times 10^8 K

Explanation:

As we know that rms speed of ideal gas is given by the formula

v_{rms} = \sqrt{\frac{3RT}{M}}

here we know that

v_{rms} = 2.67 \times 10^5 m/s

molecular mass of gas is given as

M = 44 g/mol = 0.044 kg/mol

now from above formula we have

2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}

now we have

T = 1.26 \times 10^8 K

7 0
4 years ago
A bird is standing on an electric transmission line carrying 3000 A of current. A wire like this has about 3.0 x 10-5 22 of resi
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Answer:

13.5 x 10^-9 A

Explanation:

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6 0
3 years ago
Gantt charts are A. widely used network techniques. B. not widely used. C. planning charts used to schedule resources and alloca
kotykmax [81]

Answer:

planning charts used to schedule resources and allocate time is the correct answer

Explanation:

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6 0
4 years ago
Monochromatic light falls on two very narrow slits 0.048 mm apart. successive fringes on a screen 5.00 m away are 6.5 cm apart n
atroni [7]
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
y= \frac{m \lambda D}{d}
where D=5.00 m is the distance of the screen from the slits, and 
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The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
\lambda =  \frac{yd}{mD}= \frac{(0.065 m)(0.048 \cdot 10^{-3}m)}{(1)(5.00 m)}=  6.24 \cdot 10^{-7}m

And from the relationship between frequency and wavelength, c=\lambda f, we can find the frequency of the light:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{6.24 \cdot 10^{-7}m}=4.81 \cdot 10^{14}Hz
4 0
3 years ago
An electric field of 3x10^16 n/c is needed to create a spark in the air. If the charged particles in the field are separated by
meriva
The answer of this problem is positive 3
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