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3 years ago

A battery in a radio provides stored chemical energy, which is converted into _________ energy by the radio.

Physics

2 answers:

MrRissso [65]3 years ago

7 0

Answer:

Electrical

Explanation:

The chemical energy of the battery gets converted into electrical energy to operate circuits in the radio.

Fofino [41]3 years ago

7 0

Answer:

I think the answer would be D.

Hope this helps...

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Why do sound waves move faster through the ground than through the air? A. Particles of matter are packed more loosely in the gr

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Answer:

Explanation:

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3 years ago

A 3.6-volt battery is used to operate a cell phone

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Explanation :

It is given that,

Potential energy, $V=3.6\ V$

Power dissipated, $P=0.064\ Watt$

We know that the power dissipated is given by :

$P=VI$

I is the current passing through the phone.

$I=\dfrac{P}{V}$

$I=\dfrac{0.064\ W}{3.6\ V}$

$I=0.017\ A$

I = 0.018 A

Hence, the current that passes through the phone is (1) 0.018 A.

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3 years ago

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

xz_007 [3.2K]

Answer:

a) $\Delta{t} = 5.39s$

b) the motorcycle travels 155 m

Explanation:

Let $t_2-t_1 = \Delta{t}$ , then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):

$v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}$

where:

$v_{m2}$ is the speed of the motorcycle at time 2

$v_{c}$ is the velocity of the car (constant)

$v_{0}$ is the velocity of the car and the motorcycle at time 1

d is the distance between the car and the motorcycle at time 1

x is the distance traveled by the car between time 1 and time 2

Solving the system of equations:

$\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]$

$v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s$

For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:

$x = v_0\Delta{t}= 18\sqrt{29}=96.933m\\then:\\x+d = 154.933$

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3 years ago

The speed of a sound wave traveling through air is 400 meters per second. The wavelength of the wave is 25 meters What is the

sweet [91]

Answer:

16Hz

Explanation:

Given parameters:

Speed of sound = 400m/s

Wavelength = 25m

Unknown:

Frequency of the wave = ?

Solution:

To solve this problem;

V = F ∧

V is the velocity

F is the frequency

∧ is the wavelength

400 = F x 25

F = 16Hz

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3 years ago

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Match the player positions with his or her job on the court.

velikii [3]

2.c
3.b
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3 years ago

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