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Svetllana [295]
3 years ago
12

ASAP !!!! On a hot summer day the temperature is 30.0C. what is the volume of a weather balloon that has 34.5 moles of helium at

1 atmosphere?
Chemistry
1 answer:
Strike441 [17]3 years ago
5 0
BUMMER I WISH I KNEW BUD

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How do molecules move in gas
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They become fast that they don't touch each other

Explanation:

That's it sorry that I can't help any further

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Abel and his family are going on a road trip from Rhode Island to Alabama. The drive will take 18 hours. If they leave Rohde Isl
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3 years ago
The density of thorium, which has the FCC structure, is 11.72 g/cm3. The atomic weight of thorium is 232 g/mol. Calculate (a) th
seropon [69]

Answer:

(a) a = 5.08x10⁻⁸ cm

(b) r = 179.6 pm  

Explanation:

(a) The lattice parameter "a" can be calculated using the following equation:

\rho = \frac{(N atoms/cell)*m}{V_{c}*N_{A}}      

<em>where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and </em>N_{A}<em>: is the Avogadro constant = 6.023x10²³ atoms/mol. </em>

Hence the lattice parameter is:  

a^{3} = \frac{(N atoms/cell)*m}{\rho *N_{A}} = \frac{4 atoms*232 g/mol}{11.72 g/cm^{3} *6.023 \cdot 10^{23} atoms/mol} = 1.32 \cdot 10^{-22} cm^{3}

a = \sqrt[3]{1.32 \cdot 10^{-22} cm^{3}} = 5.08 \cdot 10^{-8} cm

(b) We know that the lattice parameter of a FCC structure is:

a = \frac{4r}{\sqrt{2}}

<em>where r: is the atomic radius of Th</em>

Hence, the atomic radius of Th is:

r = \frac{a*\sqrt{2}}{4} = \frac{5.08 \cdot 10^{-8} cm*\sqrt{2}}{4} = 1.796 \cdot 10^{-8} cm = 179.6 pm    

I hope it helps you!    

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3 years ago
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Find the area of a triangle with a base of 4 meters and a height of 6 meters
RSB [31]

Answer:

24 meters

Explanation:

24 meter because area

area=Lxw

so just multiply 4 x 6 = 24

4 0
3 years ago
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