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3 years ago

What time of day does the full moon rise? (Estimate the hour: 1 pm? 2pm? etc. and explain your answer.)

Physics

1 answer:

AlexFokin [52]3 years ago

7 0

Explanation:

1. The full Moon rises just after the Sun sets. So lets assume the Sun sets at 06:00 pm then the Moon will rise at 06:00 pm. This happens because of the position of Moon with respect to Sun. It is opposite to the Sun as seen from Earth.

2. Lets assume that Sun rise will happen at 06:00 am so Moon will be visible till 06:00 am and it will reach highest point in the Sky at 00:00 am that is midnight. This is the time when it will cross the meridian line.

3. No, we can never see the Sun going through phases no matter where we are. The Moon shows us phases because it doesn't have its own light and reflects light of the Sun. But Sun is a star and has it own light. Sun will always be seen like a full circle.

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I think it is D

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Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th

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Answer:

$T_1=T_3=\dfrac{2\pi}{21}$

$T_2=T_4=\dfrac{2\pi}{42}$

Explanation:

Wave 1, $y_1=0.12\ cos(3x-21t)$

Wave 2, $y_2=0.15\ sin(6x+42t)$

Wave 3, $y_3=0.13\ cos(6x+21t)$

Wave 4, $y_4=-0.27\ sin(3x-42t)$

The general equation of travelling wave is given by :

$y=A\ cos(kx\pm \omega t)$

The value of $\omega$ will remain the same if we take phase difference into account.

For first wave,

$\omega_1=21$

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$T_1=\dfrac{2\pi}{21}$

For second wave,

$\omega_2=42$

$\dfrac{2\pi }{T_2}=42$

$T_2=\dfrac{2\pi}{42}$

For the third wave,

$\omega_3=21$

$\dfrac{2\pi }{T_3}=21$

$T_3=\dfrac{2\pi}{21}$

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$\omega_4=42$

$\dfrac{2\pi }{T_4}=42$

$T_4=\dfrac{2\pi}{42}$

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3 years ago

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