Answer:
lauda and lasan I am fine with me lit Q ans pg-14
Answer:
105000km
Explanation:
Given parameters:
Speed of shuttle = 21000km/hr
Time of travel = 5hrs
Unknown:
The distance covered by the space shuttle;
Solution:
Distance is the length of the path traveled.
Distance = speed x time
Input the parameters and solve;
Distance = 21000km/hr x 5hrs
Distance = 105000km
Bacteria have a well-earned reputation for causing disease, but now certain types of microorganisms are being put to good use by improving water cleanliness and safety. Waste water produced by factories is contaminated with heavy metals—elements that are naturally present in our bodies in small amounts, but which can be extremely dangerous to humans at higher levels of concentration. To clean this industrial waste water, it is put through the process of bioremediation, or the use of microorganisms to treat water that has been contaminated by hazardous materials. Water that has been cleaned by this method can then be released into the environment or even reused. One method of bioremediation is called biogenic hydrogen sulfide precipitation technology
Answer: 3.53 x 10^-4 s
Explanation:
12.7cm x 1m/100cm = 0.127m
V = d/t
t x V = d
t = d/v = 0.127m/(360m/s) = 0.000353s or 3.53 x 10^-4
Answer:
(a). = 5.43
(b). 13
(C) 0
Explanation:
part A:
φ(outside) = ∬B(outside) dS
note that;
φ(sum) = 2[φ(outside) + φ(inside).
then, we say
φ(outside) = ∫ μI/ 2πr dr (taking boundaries at R - d/2 and d/2.
μI/2πr dr= μI/2πr ln 2R- d/d
= 1.26× 1) ^-6 ×10 ln 40-2.5/2.5.
= 5.43 μWb.
magnetic flux in the conductor can be calculated from magnetic induction as integral of d/2 to R
please note that dS= 1. dr
φ (inside) = B(inside) dS
∫2μIr/ π d^2 dV.
μI/πd2 r^2 (at boundary d/2 and 0)
μI/4π
= 1.26×10^-6 ×10/4π.
= 1.0032 μWb .
where B(inside) = μI(inside)/ 2πr and I= Ir^2/ (d/2) ^2.
φ(sum)= φ(outside + inside)
=2(5.42 + 1.0032
= 13μWb
(c). is zero