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3 years ago

A motor has a rating power of 20 W and motor is used for 10 s. Calculate the

Physics

1 answer:

zepelin [54]3 years ago

6 0

Explanation:

oii ay school ens?

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If a pedestrian walked 900 meters forward and 300 meters back

serious [3.7K]

Answer:

Explanation:

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3 years ago

An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation

Scrat [10]

What the equation given?

x(t)=Acos $\omega$ t

Maximum velocity occurs at the equilibrium position

Now

x(0)=Acos0[/tex]
x(0)=A

Now

As we know the formula

$\\ \rm\rightarrowtail V_max=A\omega$

These expressions can be used

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3 years ago

WILL MARK YOU BRAINLIEST

stiv31 [10]

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Digital signals can convey information with less noise, distortion, and interference.

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6 0

3 years ago

A 60-W light bulb consumes 60 W of electrical power. It radiates almost all of this power, some of it in the form of visible lig

Eva8 [605]

Answer:

0.349W/m²

Explanation:

We can use the intensity formula [ I = P/T ].

= P / 4πr²

= 60/4π(3.7)²

= 60/4(3.14)(13.69)

= 60/4(42.9866)

= 60/171.9464

≈ 0.349W/m²

Best of Luck!

3 0

2 years ago

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of fricti

RideAnS [48]

Answer:

Maximum speed of the car is 26.56 m/s.

Explanation:

Given that,

Mass of the car, m = 1200 kg

Radius of the curve, r = 90 m

The coefficient of friction between tires and the road is 0.8.

We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

$\dfrac{v^2}{r}=\mu g\\\\v=\sqrt{\mu gr} \\\\v=\sqrt{0.8\times 9.8\times 90} \\\\v=26.56\ m/s$

So, the maximum speed of the car is 26.56 m/s.

5 0

3 years ago