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ira [324]
3 years ago
6

When one does twice the work in twice the time, the power expended is

Physics
1 answer:
devlian [24]3 years ago
8 0

Answer:

the same.

hope this helps!

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The owner of a company that manufactures drinking cups decides it would be impressive to build an inground swimming pool that is
garri49 [273]

Answer:

The depth is 5.15 m.

Explanation:

Lets take the depth of the pool = h m

The atmospheric pressure ,P = 101235 N/m²

The area of the top = A m²

The area of the bottom =  a m²

Given that A= 1.5 a

The force on the top of the pool = P A

The total pressure on the bottom = P + ρ g h

ρ =Density of the  water = 1000 kg/m³

The total pressure at the bottom of the pool =  (P + ρ g h) a

The bottom and the top force is same

(P + ρ g h) a = P A

P a +ρ g h a =  P A

ρ g h a =  P A - P a

h=\dfrac{P ( A-a)}{\rho g a}

h=\dfrac{P ( 1.5 a-a)}{\rho g a}

h=\dfrac{P ( 1.5- 1)}{\rho g}

h=\dfrac{101235 ( 1.5- 1)}{1000\times 9.81}\ m

h=5.15 m

The depth is 5.15 m.

7 0
3 years ago
Except for the nodes on a standing wave, what is the frequency f of the points executing simple harmonic motion?
Katen [24]

Take into account that in a standing wave, the frequency f of the points executing simple harmonic motion, is simply a multiple of the fundamental harmonic fo, that is:

f = n·fo

where n is an integer and fo is the first harmonic or fundamental.

fo is given by the length L of a string, in the following way:

fo = v/λ = v/(L/2) = 2v/L

becasue in the fundamental harmonic, the length of th string coincides with one hal of the wavelength of the wave.

6 0
1 year ago
g a mass of 1.3 kg is pushed horizontally against a massless spring with a spring constant of 58 n/m until the spring compresses
ExtremeBDS [4]

Answer: 1.102\ J

Explanation:

Given

Mass m=1.3\ kg

Spring constant k=58\ N/m

Compression in the spring x=19.5\ cm\ or\ 0.195\ m

When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J

The kinetic energy of the mass is 1.102 J.

5 0
3 years ago
What is the physics definition of work? How is work calculated? How would you calculate the amount of work done in a slapshot.
loris [4]

Answer:

1) Work is a measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. 2) Work is calculated through joules. 3) It's possible to calculate work by multiplying the amount of force applied by the distance that the force is applied. If we know the amount of force the stick applies to the puck and the distance that the stick is applying the force to the puck, we can figure out the amount of work done.

Explanation:

Hope this helped!- Nya~ :3

3 0
3 years ago
The elastic energy stored in your tendons can contribute up to 35%% of your energy needs when running. Sports scientists find th
zzz [600]

Answer:

11.16 J

Explanation:

Elastic energy (E) stored in the tendon is given by 1/2ke^2

SPRINTERS

k = 31N/mm = 31N/mm × 1000mm/1m = 31,000N/m

e = 41mm = 41mm × 1m/1000mm = 0.041m

E = 1/2 × 31,000 × 0.041^2 = 26.06J

NON-ATHLETES

k = 31,000N/m

e = 31mm = 31mm × 1m/1000 = 0.031m

E = 1/2 × 31,000 × 0.031^2 = 14.90 J

Difference = 26.06 J - 14.90 J = 11.16 J

4 0
3 years ago
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