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3 years ago

determine the rate of a reaction that follows the rate law: rate=k[A]m[B]n, where: k= 1x10-2 [A]=2 M B= 3 M m=2 n=1?

Chemistry

1 answer:

victus00 [196]3 years ago

7 0

Answer:

0.12 molL‐¹ s‐¹

Explanation:

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A 5.000 g mixture contains strontium nitrate and potassium bromide. Excess lead(II) nitrate solution is added to precipitate out

scZoUnD [109]

Answer: The mass percent of potassium bromide in the mixture is 9.996%

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For lead (II) bromide:

Given mass of lead (II) bromide = 0.7822 g

Molar mass of lead (II) bromide = 367 g/mol

Putting values in equation 1, we get:

$\text{Moles of lead (II) bromide}=\frac{0.7822g}{367g/mol}=0.0021mol$

The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:

$2KBr+Pb(NO_3)_2\rightarrow PbBr_2+2KNO_3$

By Stoichiometry of the reaction:

1 mole of lead (II) bromide is produced from 2 moles of potassium bromide

So, 0.0021 moles of lead (II) bromide will be produced from = $\frac{2}{1}\times 0.0021=0.0042mol$ of potassium bromide

Now, calculating the mass of potassium bromide by using equation 1, we get:

Molar mass of KBr = 119 g/mol

Moles of KBr = 0.0042 moles

Putting values in equation 1, we get:

$0.0042mol=\frac{\text{Mass of KBr}}{119g/mol}\\\\\text{Mass of KBr}=0.4998g$

To calculate the percentage composition of KBr in the mixture, we use the equation:

$\%\text{ composition of KBr}=\frac{\text{Mass of KBr}}{\text{Mass of mixture}}\times 100$

Mass of mixture = 5.000 g

Mass of KBr = 0.4998 g

Putting values in above equation, we get:

$\%\text{ composition of KBr}=\frac{0.4998g}{5.000g}\times 100=9.996\%$

Hence, the percent by mass of KBr in the mixture is 9.996 %

5 0

3 years ago

What is the frequency of radiation whose wavelength is 2.25 X 10^-5cm?

Semenov [28]

Answer:

1.25 x 10^15Hz

Explanation:

c = frequency x wavelength

c is the speed of light, which is equal to 3.00 x 10^8 m / s

frequency = c /wavelength

= (3.00 x 10^8m /s) / (2.40 x 10^-5 cm x 1 m /100cm)

= (3.00 x 10^8 m/s) / 2.40 x 10^-7m

= 1.25 x 10^15/s 1 / s = 1Hz

So, the Frequency = 1.25 x 10^15Hz

I hope this helped :)

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