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3 years ago

15

Baking powder, baking soda, and creme of tartar are three substances that have similar properties. Explain what these three subs

tances have in common.

1 answer:

jarptica [38.1K]3 years ago

4 0

they are all catalysts

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Bad White [126]

Answer:

thick, insulating fur

Explanation:

If an animal lives in a freezing climate, it makes sense logically that the animal would adapt and develop a layer of thick fur to keep its body insulated and maintain homeostasis.

Hope this helped and please consider a Brainliest! :)

5 0

3 years ago

Read 2 more answers

Classify each of the coordination compounds according to the coordination number.

amid [387]

Coordination number has to do with the number of ligands that is attched to the central metal atom/ion.

<h3>What is coordination number?</h3>

The term coordination number has to do with the number of ligands that is attched to the central metal atom/ion. The coordination sphere contains this central metal along with associated ligands.

The question is incomplete. However, if I have something like, K3[Cr(H2O)6], the coordination number of the complex is six.

Learn mlore about coordination number: brainly.com/question/16236454

3 0

2 years ago

The following mechanism has been suggested for the reaction between nitrogen monoxide and oxygen: NO(g) + NO(g) → N2O2(g) (fast)

Karo-lina-s [1.5K]

Answer:

b. Second order in NO and first order in O₂.

Explanation:

A. The mechanism

$\rm 2NO\xrightarrow[k_{-1}]{k_{1}}N_{2}O_{2} \, (fast)\\\rm N_{2}O_{2} + O_{2}\xrightarrow{k_{2}} 2NO_{2} \, (slow)$

B. The rate expressions

$-\dfrac{\text{d[NO]} }{\text{d}t} = k_{1}[\text{NO]}^{2} - k_{-1} [\text{N}_{2}\text{O}_{2}]^{2}\\\\\rm -\dfrac{\text{d[N$_{2}$O$_{2}$]}}{\text{d}t} = -\dfrac{\text{d[O$_{2}$]}}{\text{d}t} = k_{2}[ N_{2}O_{2}][O_{2}] - k_{1} [NO]^{2}\\\\\dfrac{\text{d[NO$_{2}$]}}{\text{d}t}= k_{2}[ N_{2}O_{2}][O_{2}]$

The last expression is the rate law for the slow step. However, it contains the intermediate N₂O₂, so it can't be the final answer.

C. Assume the first step is an equilibrium

If the first step is an equilibrium, the rates of the forward and reverse reactions are equal. The equilibrium is only slightly perturbed by the slow leaking away of N₂O₂ to form product.

$\rm k_{1}[NO]^{2} = k_{-1} [N_{2}O_{2}]\\\\\rm [N_{2}O_{2}] = \dfrac{k_{1}}{k_{-1}}[NO]^{2}$

D. Substitute this concentration into the rate law

$\rm \dfrac{\text{d[NO$_{2}$]}}{\text{d}t}= \dfrac{k_{2}k_{1}}{k_{-1}}[NO]^{2} [O_{2}] = k[NO]^{2} [O_{2}]$

The reaction is second order in NO and first order in O₂.

8 0

3 years ago

Carbon 14 is an example of blank dating

Brilliant_brown [7]

Answer:

Carbon

Explanation:

It's in the name lol

6 0

3 years ago

If the forward reaction goes close to completion and has a high yield, what is the expected value of the equilibrium constant (k

Anna007 [38]

If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants.

<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
</span><span>
Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>

8 0

3 years ago