The distinguish between each pair of compounds using high- resolution mass spectrometry by the exact mass rather than nominal mass are utilizes to measure the compound.
The mass spectrometry is involves the following steps :
- The ionization
- acceleration
- deflection
- detection
Mass spectrometry is the analytical method useful for the calculating the mass to charge ratio ( m / z ). the mass spectrometry is based on the newton's second law and the momentum.
Thus, the mass spectroscopy is method to measure the molecular mass of the compound and indirectly helps examine the isotopes and based on the newton's second law .
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...a metal atom will *lose* electrons to form a *positive* cation and a nonmetal atom will *accept* electrons to form an *negative* anion.
Answer:
The group 18 elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements are non-reactive and are called noble gases as they have their outermost orbit complete. Due to stable electronic configuration they hardly react with other elements.The name comes from the fact that these elements are virtually unreactive towards other elements or compounds.The group 18 elements are called noble or inert gases. As the name suggests these are inert because chemically they are very less reactive or not at all reactive.The full valence electron shells of these atoms make the noble gases extremely stable.
42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.
<h3>What is a graduated cylinder?</h3>
A tall narrow container with a volume scale is used especially for measuring liquids.
The graduated cylinder contains water
mL is a volume unit.
Water volume = 50.6 ml
The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.
The new volume is the lead ball volume plus the original water volume :
Final volume = Vlead ball+ Water original volume
![93.0 mL= V_(lead ball) +50.6 ml](https://tex.z-dn.net/?f=93.0%20mL%3D%20V_%28lead%20ball%29%20%2B50.6%20ml)
![V_(lead ball) = 93.0 mL - 50.6 ml](https://tex.z-dn.net/?f=V_%28lead%20ball%29%20%3D%2093.0%20mL%20-%2050.6%20ml)
![V_(lead ball) = 42.4 ml](https://tex.z-dn.net/?f=V_%28lead%20ball%29%20%3D%2042.4%20ml)
Hence, 42.4 ml is the volume in milliliters of the lead ball.
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