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3 years ago

Ampres law is often written contourintegral B vector (r vector) middot dl vector = mu_0I_enclosed. The integral on the left is

Physics

1 answer:

uranmaximum [27]3 years ago

4 0

Answer:

This integral is evaluated by dividing the path into infinitesimal segments dL, calculating the scalar product B•dL for each segment, and sum these products. The component of B parallel to dL at each point is always used in evaluating this integral.

The line integral is equal to mu_o × I.

Explanation:

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Which of these statements is true? controlled data produces valid experiments. controlled experiments produce valid data. valid

Brums [2.3K]

Each of the choices may be considered right depending on the use of context or on how terms are defined, but the one that is most correct is:

"Controlled experiments produce valid data"

Controlled experiments are experiments in which factors which are not the interest of the study or which are not being studied are controlled or accounted for in the design, so that resulting data are less likely to be caused by some anomaly or by some variable other than those being studied. In usual research scenarios it is not the data itself that is acted upon in the <span>experiment - it is the experiment itself, the factors and the physical processes that will eventually yield data.</span>

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3 years ago

Read the following story and tell me how Harper used the FITT principle. Harper works out 4-5 days a week for 60 minutes a day.

sweet [91]

Harper used the the frequency principle (F) by planning to work out 4-5 days a week. Frequency is how often you exercise, usually on a weekly basis.

She used the intensity principle (I) by deciding to exercise on a moderate level, rather than, for example, an intense workout. Intensity is basically how hard you exercise and push yourself.

She then used the time (T) principle by choosing to workout for 60 mins per day. Time meaning how much time you spend working out each day.

And lastly, she used the type (T) principle by devising a specific type and/or set of exercise(s) to do, which in her case, is drills, jogging, and weight lifting.

So all in all, Harpers frequency is 4-5 days per week, her intensity is moderate, her time is 60 mins/day, and type is basketball drills, jogging and weight lifting.

Hope I helped! :)

7 0

3 years ago

If I travel 100 m N in 5 seconds, what is my average velocity?

Nina [5.8K]

Answer:

Explanation:

$Average- velocity = \frac{displacement }{time} \\A.V = \frac{100}{5} \\A.V = 20$

3 0

3 years ago

Read 2 more answers

The freight cars a and b have a mass of 20 mg and 15 mg, respectively. if the cars collide and couple together, what is the velo

igomit [66]

Suppose car A is moving with a velocity Va, and car b with a velocity Vb,

According the principle of conservation of momentum:

Va x Ma + Vb x Mb = (Ma + Mb) V

V = (Va x Ma + Vb x Mb)/(Ma +Mb)

V = speed of cars after coupling

V = (Va x 20 mg + Vb x 15 mg)/(20 mg + 15 mg)

Put in the values of Va and Vb, and get the V

7 0

3 years ago

Read 2 more answers

Tarzan (mT=85.0 kg) is perched on a cliff 16.0 m above Jane. Jane is in the foreground is looking forwards. In the background, T

poizon [28]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Part A

The velocity of Tarzan is $v_T = 17.7 \ m/s$

Part B

The percentage loss of kinetic energy is %-loss $= 61.4$ %

Part C

The speed would be exactly the same

Explanation:

From the question we are told that

The mass of Tarzan is $m = 85.5 \ kg$

The height of the cliff is $h = 16.0 \ m$

From the law of conservation of energy

$PE = KE$

Where PE is the potential energy of Tarzan at the top of the cliff which is mathematically represented as

$PE = mgh$

KE is the kinetic energy of Tarzan as he swings toward jane and is mathematically represented as

$KE = \frac{1}{2} mv^2_T$

$mgh = \frac{1}{2}m v_T^2$

=> $gh = \frac{1}{2} v_T^2$

Substituting values

$9.8 * 16 = \frac{1}{2} v_T^2$

=> $v_T = \sqrt{\frac{9.8 * 16}{0.5} }$

$v_T = 17.7 \ m/s$

From the question we are told that the actual velocity of Tarzan is

$v = 11 m/s$

The kinetic energy at the the velocity is mathematically represented as

$KE_A = \frac{1}{2} m v^2$

Substituting values

$KE_A = \frac{1}{2} (85) * 11^2$

$KE_A = 5142.5 J$

The kinetic energy at $v_T$ is

$KE = \frac{1}{2} * 85 * 17.7^2$

=> $KE = 13314.83\ J$

Now the percentage loss of kinetic energy is mathematically evaluated as

%-loss $= \frac{KE - KE_A}{KE} * 100$

substituting values

%-loss $= \frac{13314.83 - 5142.5}{13314.83} * 100$

%-loss $= 61.4$ %

The mass of Tarzan does not affect the speed because looking at this equation

$gh = \frac{1}{2} v_T^2$

We see that the velocity of Tarzan is not dependent on the mass of Tarzan

4 0

3 years ago