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velikii [3]
3 years ago
6

An L−R−C series circuit has 91.5 Ω , and the amplitude of the voltage across the resistor is 36.0 V . What is the average power

delivered by the source? Express your answer with the appropriate units.
Physics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

14.16 W

Explanation:

We have given impedance Z=91.5 ohm

Voltage across the resistor = 36 V

We have to find the power delivered by the source

We know that according to telegens theorem , the absorbed = power delivered

So the voltage across the resistor = 36 V

Current in the RLC circuit i=\frac{V}{Z}=\frac{36}{91.5}=0.3934A this current will be same in the whole circuit as it is a series RLC circuit

Now the power absorbed by the resistor P=i^2R=0.3934^2\times 91.5=14.16W

As the power absorbed = power delivered

So power delivered by the source =14.16 W

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