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velikii [3]
3 years ago
6

An L−R−C series circuit has 91.5 Ω , and the amplitude of the voltage across the resistor is 36.0 V . What is the average power

delivered by the source? Express your answer with the appropriate units.
Physics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

14.16 W

Explanation:

We have given impedance Z=91.5 ohm

Voltage across the resistor = 36 V

We have to find the power delivered by the source

We know that according to telegens theorem , the absorbed = power delivered

So the voltage across the resistor = 36 V

Current in the RLC circuit i=\frac{V}{Z}=\frac{36}{91.5}=0.3934A this current will be same in the whole circuit as it is a series RLC circuit

Now the power absorbed by the resistor P=i^2R=0.3934^2\times 91.5=14.16W

As the power absorbed = power delivered

So power delivered by the source =14.16 W

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When a cube is inscribed in a sphere of radius r, the length Lof a side of the cube is . If a positive point charge Qis placed a
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Answer:

  Ф_cube /Ф_sphere = 3 /π

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      Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

       Фi = ∫ E .dA = q_{int} / ε₀

the Gaussian surface is a sphere so its area is

        A = 4 π r²

the charge inside is

        q_{int} = Q

we substitute

       E 4π r² = Q /ε₀

       E = 1 / 4πε₀   Q / r²

To calculate the flow on the two surfaces

* Sphere

       Ф = E A

        Ф = 1 / 4πε₀  Q / r² (4π r²)

        Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

          r = d / 2

We look for the diagonal with the Pythagorean theorem

         d² = L² + L² = 2 L²

         d = √2 L

         

we substitute

          r = √2 / 2 L

          r = L / √2

          L = √2  r

now we can calculate the area of ​​the cube that has 6 faces

          A = 6 L²

          A = 6 (√2  r)²

          A = 12 r²

the flow is

          Ф = E A

          Ф = 1 / 4πε₀  Q/r²  (12r²)

          Ф_cubo = 3 /πε₀  Q

the relationship of these two flows is

         Ф_cube /Ф_sphere = 3 /π

8 0
3 years ago
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