How can people control sound?

What feature of the ocean allows it to alter weather problems its water releases hydrogen that creates cold fronts its rising ti

katrin2010 [14]

<span>The size of the ocean, along with the large heat capacity of water,
allows the ocean to store large amounts of heat energy.</span>

6 0

4 years ago

Read 2 more answers

A metal cube measures 15 cm on a side and has a density of 6920 kg/m^3. Find the mass in grams.

soldi70 [24.7K]

Answer:

Mass of the cube is 23350 grams.

Explanation:

It is given that,

Side of cube, a = 15 cm = 0.15 m

Density of the cube, $d=6920\ kg/m^3$

We need to find its mass. It can be calculated using the formula of density as :

$d=\dfrac{m}{V}$

$m=d\times V$ , V is the volume of cube

$m=d\times a^3$

$m=6920\ kg/m^3\times (0.15\ m)^3$

m = 23.35 kg

or

m = 23350 grams

So, the mass of the metal cube is 23350 grams. Hence, this is the required solution.

8 0

3 years ago

What force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2000-kg car (a large car) resti

Nataliya [291]

Archimedes principle states that

F1 / A1 = F2 / A2

F2 = (A2 / A1) * F1

Also, formula for the force is F = mg. Formula for the area of the cylinder is A = πr^2, therefore we get

F2 = (πr2^2 / πr1^2) * mg

Since the diameter of the cylinders are 2 cm and 24 cm, r1 = 12 and r2 = 1.

Substituting the values to the derived equation, we get

F2 = (π 1^2 / π 12^2) * 2400 * 9.8

F2 = 163.3333 N

6 0

3 years ago

A copper wire and a tungsten wire of the same length have the same resistance. What is the ratio of the diameter of the copper w

spayn [35]

Answer:

Therefore the ratio of diameter of the copper to that of the tungsten is

$\sqrt{3} :\sqrt{10}$

Explanation:

Resistance: Resistance is defined to the ratio of voltage to the electricity.

The resistance of a wire is

directly proportional to its length i.e $R\propto l$
inversely proportional to its cross section area i.e $R\propto \frac{1}{A}$

Therefore

$R=\rho\frac{l}{A}$

ρ is the resistivity.

The unit of resistance is ohm (Ω).

The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m

The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m

For copper:

$A=\pi r_1^2 =\pi (\frac{d_1}{2} )^2$

$R_1=\rho_1\frac{l_1}{\pi(\frac{d_1}{2})^2 }$

$\Rightarrow (\frac{d_1}{2})^2=\rho_1\frac{l_1}{\pi R_1 }$ ......(1)

Again for tungsten:

$R_2=\rho_2\frac{l_2}{\pi(\frac{d_2}{2})^2 }$

$\Rightarrow (\frac{d_2}{2})^2=\rho_2\frac{l_2}{\pi R_2 }$ ........(2)

Given that $R_1=R_2$ and $l_1=l_2$

Dividing the equation (1) and (2)

$\Rightarrow\frac{ (\frac{d_1}{2})^2}{ (\frac{d_2}{2})^2}=\frac{\rho_1\frac{l_1}{\pi R_1 }}{\rho_2\frac{l_2}{\pi R_2 }}$

$\Rightarrow( \frac{d_1}{d_2} )^2=\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}$ [since $R_1=R_2$ and $l_1=l_2$ ]

$\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}}$

$\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{3}{10}}$

$\Rightarrow d_1:d_2=\sqrt{3} :\sqrt{10}$

Therefore the ratio of diameter of the copper to that of the tungsten is

$\sqrt{3} :\sqrt{10}$

8 0

4 years ago

Magnetic Field of a Current Loop: A wire carrying a current is shaped in the form of a circular loop of radius 4.0 mm. If the ma

mr_godi [17]

Answer:

The magnitude of the current flowing through the wire is 7 A.

Explanation:

Given that,

Radius of the circular loop, r = 4 mm = 0.004 m

Magnetic field at the centre of the loop, B = 1.1 mT

We need to find the magnitude of the current flowing through the wire. The magnetic field at the center of the loop is given by the formula as follows :

$B=\dfrac{\mu_oI}{2r}\\\\I=\dfrac{2Br}{\mu_o}\\\\I=\dfrac{2\times 1.1\times 10^{-3}\times 0.004}{4\pi \times 10^{-7}}\\\\I=7\ A$

So, the magnitude of the current flowing through the wire is 7 A.

4 0

4 years ago