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Ilya [14]
3 years ago
13

The specific heat of a certain type of cooking oil is 1.75 cal/ (g c) how much heat energy is needed to raise the temperature of

2.67 kg of this oil from 23 c to 191 c
Chemistry
1 answer:
sineoko [7]3 years ago
4 0

Just use the formula:


Q = cMΔT


where

Q = heat energy needed for that material to get desired temperature change (in Joules)

M = mass (in grams) so you have to convert from kilograms.

c = specific heat constant for the material being heated [in /(grams oC)]

ΔT = change in temperature (in oC)

Q = (1.75)(2.17 x 1000)(191 - 23) = (1.75)(2170)(168) = 637,980 Joules

hope that helps you in some way

also have a great day!

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<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

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A dilution is mathematically expressed as:

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In this case, you know:

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