Answer:
8.937g/cm³
Explanation:
To answer this question we need to know that, in 1 unit FCC cell you have:
Edge length = √8 * R
<em>Volume = 8√8 * R³</em>
<em>And there are 4 atoms per unit cell</em>
<em />
<em>Mass of 4 atoms in g:</em>
4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g
<em />
<em>Volume in cm³:</em>
0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm
Volume = 8√8 * (1.278x10⁻⁸cm)³
Volume = 4.723x10⁻²³cm³
And density is:
4.221x10⁻²²g / 4.723x10⁻²³cm³ =
<h3>8.937g/cm³</h3>
Answer:
328 ml
Explanation:
We have given final volume =575.2 ml=0.575 L
Final concentration = 0.8012 M
We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles
We have to find initial volume
So initial volume 
Answer:
Mass = 25.08 g
Explanation:
Given data:
Volume of fluorine = 29.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Mass of fluorine = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K
n = 1.32 mol
Mass of fluorine:
Mass = number of moles × molar mass
Mass = 1.32 mol ×19 g/mol
Mass = 25.08 g
Answer:
Cryogenic distillation
Explanation:
Cryogenic Distillation is the process in which Nitrogen and Oxygen are separated from air. Thus in cryogenic distillations the components having very low boiling points are distilled selectively at low temperatures. This method produces products of high purity but also it is quite energy intensive.
