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ICE Princess25 [194]
3 years ago
3

Assume that you want to construct a voltaic cell that uses the following half reactions:

Chemistry
1 answer:
disa [49]3 years ago
7 0
I think it’s A cause they should add enough
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Consider the balanced equation below.
Vikki [24]

Answer: The mole ratio of PCl_3 to PCl_5 is 1: 1

Explanation:

According to the balanced chemical equation ,the number of atoms of each element has to be same on reactant and product side. The stoichiometric coefficients of the species represent their number of moles.

PCl_3+Cl_2\rightarrow PCl_5

Thus in the reactants, there is 1 mole of PCl_3 and 1 mole of Cl_2 molecule. And thus there is 1 mole of PCl_5 in the product as well.

Thus the mole ratio of PCl_3 to PCl_5 is 1: 1

5 0
3 years ago
Someone help please ...
Tanzania [10]

Answer:

Yes

Explanation:

4 0
3 years ago
If the average atomic mass of hydrogen in nature is 1.0079, what does that tell you about the percent composition of H-1 and H-2
vovangra [49]

Answer:

That the isotope H-1 is the most abundant in nature.

Explanation:

Hello!

In this case, since the average atomic mass of an element is computed considering the mass of each isotope and the percent abundance each, for hydrogen we would set up something like this:

m_H=m_{H_1}*\%abund_{H_1}+m_{H_2}*\%abund_{H_2}

Moreover, since the isotope notation H-1 and H-2 means that the atomic mass of H-1 is 1 amu, that of H-2 is 2 amu and the average one is 1.0079 amu, we can infer that the most of the hydrogen in nature is H-1 as the most of it composes the average hydrogen atom.

Best regards!

4 0
3 years ago
1. Explain how groups 1A-8A in the periodic table are organized by their number of valence electrons.
nirvana33 [79]

Explanation:

1. Explain how groups 1A-8A in the periodic table are organized by their number of valence electrons.

The valence electrons in an atom are the outermost shell electrons. They are the most loosely held electrons in an atom.

Coincidentally, the periodic table of elements divided into vertical groups and horizontal periods can be said to be arranged according to the number of valence electrons.

  • Atomic numbers are used to arrange elements on the periodic table.
  • Down a group, the number of electronic shell increases. More electrons are added to new energy levels.
  • As we move from left to right across a period, the number of electrons in elements increases but electronic shell is the same.
  • Down a group electronic shell increases but the number of valence electrons are the same.
  • All elements in Group 1A has just one valence electrons, Group 2A has two valence electrons.........Group 8A has eight valence electrons.
  • Moving across groups is synonymous to moving from left to right on the periodic table.
  • Due to this trend, the periodic table is arranged based on the number of valence electrons.

3. explain how you know the number of valence electrons for each group.

The number of valence electrons in a group is the group number:

   Group      Number                     valence electrons

              1A                                                 1

              2A                                                2

              3A                                                 3

              4A                                                 4

               5A                                                5

               6A                                                6

               7A                                                7

               8A                                                8

learn more:

Periodic table brainly.com/question/1971327

#learnwithBrainly

6 0
3 years ago
The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
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