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3 years ago

Assume that you want to construct a voltaic cell that uses the following half reactions:

Chemistry

1 answer:

disa [49]3 years ago

7 0

I think it’s A cause they should add enough

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In which of the following does the land being moved contin approximately 60% water

sp2606 [1]

Answer:

Explanation:

The answer is C because only that amount can move

4 0

3 years ago

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A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal

Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m) = 16.59 g

Volume (v) = 5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

$p = \frac{m}{v}$

Substitute the values into the formula:

$p = \frac{16.59 g}{5.81 mL} \\ = 2.8554 g/mL$

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0

1 year ago

What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?

kotykmax [81]

The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution
there are 1.00 mol in 1 L of solution
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L
volume of HCl required is 0.150 L

3 0

3 years ago

What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)

My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ → 2KCl + 3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1 .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0

3 years ago

Identify the for of energy (A)thermal (B)kinetic (C)chemical (D)electrical

RoseWind [281]

Answer:

C Chemical Energy

Explanation:

food gives us chemical energy which may be transformed to other later..

please mark me brainliest

3 0

3 years ago

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