7 cheese pizzas and 38 pepperoni pizzas were sold.
Step-by-step explanation:
Given,
Cost of one pepperoni pizza = $8.50
Cost of one cheese pizza = $6.00
Total pizzas sold = 45
Total worth = $365
Let,
x be the number of pepperoni pizzas sold.
y be the number of cheese pizzas sold.
According to given statement;
x+y=45 Eqn 1
8.50x+6y=365 Eqn 2
Multiplying Eqn 1 by 6

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 2.50

Putting x=38 in Eqn 1

7 cheese pizzas and 38 pepperoni pizzas were sold.
Keywords: linear equation, subtraction
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