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3 years ago

Yamil is observing a fossil insect preserved in amber.

2 answers:

5 0

Fossil Insects (Many specimens are amber inclusions). Fossil Amber or Fossil Resin. Phasmida or Walking Stick in Fossil Amber Amber is the popular name forfossilized resin of botanical origin. The proper scientific terminology is fossil resin, but we will use the terms amber and ...

Lunna [17]3 years ago

5 0

Answer:

The fossils like insects and flies are often found to be trapped in the amber. The amber refers to the fossilized resins of trees, that are very sticky and are similar to honey. When an insect or a fly falls on it accidentally, it gets attached to the resin, as a result of which it becomes difficult for them to move out of it and over millions of years, it turns into a fossil.

These data can be obtained by observing a fossil that is trapped in amber.

In order to study these fossils, some of the tools such as a microscope, slides, and handheld jewelers are commonly used. These tools help in acquiring the data that are needed to understand the detailed information regarding these fossils. The slides are used to place the fossil sample in it and are observed under the microscope at different magnification.

Thus, these fossils are very useful in studying the past environment, food habitat and climatic conditions in which they lived.

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Plete the following problems significant figures: 6 × 0.30

jeka57 [31]

6= Only the digits 1 and 6 are the actual measured values. Therefore we have only 2 significant figures.

0.3= Zeros used as placeholders are not significant. Zeros that come before non-zero integers are never significant. Example 5: The zeros in 098, 0.3, and 0.000000000389 are not significant because they are all in front of non-zero integers. c. If the zeros come after non-zero integers and are followed by a decimal point, the zeros are significant.

3 0

3 years ago

Please help me ASAP

MrRissso [65]

Answer:

<h2>answer will be D</h2>

change of state only 

8 0

4 years ago

What is a nonpolar bond?

Ierofanga [76]

Answer:

Nonpolar covalent bonds are a type of bond that occurs when two atoms share a pair of electrons with each other. These shared electrons glue two or more atoms together to form a molecul

Explanation:

7 0

3 years ago

Two solutions namely, 500 ml of 0.50 m hcl and 500 ml of 0.50 m naoh at the same temperature of 21.6 are mixed in a constant-pre

weeeeeb [17]

24.6 ℃

<h3>Explanation</h3>

Hydrochloric acid and sodium hydroxide reacts by the following equation:

$\text{HCl} \; (aq) + \text{NaOH} \; (aq) \to \text{NaCl} \; (aq) + \text{H}_2\text{O} \; (aq)$

which is equivalent to

$\text{H}^{+} \; (aq) + \text{OH}^{-} \; (aq) \to \text{H}_2\text{O}\; (l)$

The question states that the second equation has an enthalpy, or "heat", of neutralization of $-56.2 \; \text{kJ}$ . Thus the combination of every mole of hydrogen ions and hydroxide ions in solution would produce $56.2 \; \text{kJ}$ or $56.2 \times 10^{3}\; \text{J}$ of energy.

500 milliliter of a 0.50 mol per liter "M" solution contains 0.25 moles of the solute. There are thus 0.25 moles of hydrogen ions and hydroxide ions in the two 0.500 milliliter solutions, respectively. They would combine to release $0.25 \times 56.2 \times 10^{3} = 1.405 \times 10^{4} \; \text{J}$ of energy.

Both the solution and the calorimeter absorb energy released in this neutralization reaction. Their temperature change is dependent on the heat capacity C of the two objects, combined.

The question has given the heat capacity of the calorimeter directly.

The heat capacity (the one without mass in the unit) of water is to be calculated from its mass and specific heat.

The calorimeter contains 1.00 liters or $1.00 \times 10^{3} \; \text{ml}$ of the 1.0 gram per milliliter solution. Accordingly, it would have a mass of $1.00 \times 10^{3} \; \text{g}$ .

The solution has a specific heat of $4.184 \; \text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1}$ . The solution thus have a heat capacity of $4.184 \times 1.00 \times 10^{3} = 4.184 \times 10^{3} \; \text{J} \cdot\text{K}^{-1}$ . Note that one degree Kelvins K is equivalent to one degree celsius ℃ in temperature change measurements.

The calorimeter-solution system thus has a heat capacity of $4.634 \times 10^{3} \; \text{J} \cdot \text{K}^{-1}$ , meaning that its temperature would rise by 1 degree celsius on the absorption of 4.634 × 10³ joules of energy. $1.405 \times 10^{4} \; \text{J}$ are available from the reaction. Thus, the temperature of the system shall have risen by 3.03 degrees celsius to 24.6 degrees celsius by the end of the reaction.

4 0

3 years ago

What is the potential energy of a 2-kg book sitting on a shelf 2 meters above the ground?

lys-0071 [83]

Answer:

Explanation:

What is the potential energy of a 2-kg book sitting on a shelf 2 meters above the ground?

PE = MGH, that is, potential energy = mass x gravity x height.

2*2*9.8=

39.2 joules

8 0

2 years ago