Answer: V=67.2 L
Explanation:
For this problem we will need to use the Ideal Gas Law.
Ideal Gas Law: PV=nRT
P=1.00 atm (STP)
V=?
n=3.00 mol
R=0.08206Latm/Kmol
T=273.15 K (STP)
To find V, we would manipulate the equation to V=nRT/P


With significan figures, our answer is V=67.2 L.
<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams
<u>Explanation:</u>
We are given:
Moles of calcium hydroxide = 2.70 moles
The chemical equation for the reaction of calcium hydroxide and HCl follows:

By Stoichiometry of the reaction:
1 mole of calcium hydroxide produces 2 moles of water
So, 2.70 moles of calcium hydroxide will produce =
of HCl
To calculate mass for given number of moles, we use the equation:
Molar mass of water = 18 g/mol
Moles of water = 5.40 moles
Putting values in above equation, we get:

Hence, the mass of water produced in the reaction is 97.2 grams
Answer:
Y³⁻ A non metal that gained three electrons.
V²⁺ A metal that lost two electron
Z²⁻ A non metal that gained two electrons
X³⁺ A metal that lost three electrons
Explanation:
Metals lost the electrons and form cation
while non metals gain the electrons and form anion.
Y³⁻
c) A non metal that gained three electrons.
Non metal gain three electrons and form anion with the charge of -3.
V²⁺
a) A metal that lost two electron
A metal lost two electrons and form cation with charge of +2.
Z²⁻
d) A non metal that gained two electrons
A non metal that gained two electrons and form anion with charge of -2.
X³⁺
b) A metal that lost three electrons
A metal that lost three electrons and form cation with charge of +3.