Answer:
Step-by-step explanation:
hello :
f(x) = 2x +1 and g(x) = x².
(gºf)(a)= g(f(a)) = g(2a+1) = (2a+1)² = 4a²+4a+1
Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
The line can be written in the form y=mx+b. Plugging -2 in for m , 1 in for x, and -3 in for y, we get -3=-2*1+b=-2+b. Adding 2 to both sides, we get b=-1 and our equation turns into y=-2x-1 since y and x stay variables. Plugging it into a graphing calculator, we get in (0,b) that b = -1
1.301
Explanation:
Given:
and 
Note that from the properties of logarithms,
Answer: 2,3,5
Step-by-step explanation:
the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 2 squared × 3 × 5.
