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3 years ago

Base 6 millimeters height 4 millimeters

Mathematics

1 answer:

aksik [14]3 years ago

7 0

What are you trying to work out?

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A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so

mamaluj [8]

Answer:

1) Is the pattern an arithmetic sequence?

Yes it is

2)Identify a and d.

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.

50th term = 100

4) Find the total number of logs in the first 10 rows.

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?

Yes it is

2) Identify a and d.

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

7 0

3 years ago

Parker is putting down tiles in his kitchen, his kitchen is 10 feet long and 6 feet wide. Each tile is equal to 1 square foot an

KengaRu [80]

Answer:20

Step-by-step explanation:

2929

6 0

2 years ago

Kat has 19 coins, all quarters and dimes, that are worth a total of $4. The system of equations that can be used to find the num

pishuonlain [190]

14 is the answerrrrr

6 0

2 years ago

Read 2 more answers

Chase has 3 gallons of a solution that is 30% antifeeze that he wants to use to winterize his car. How much pure antifreeze shou

makvit [3.9K]

Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.

There are 30% of pure antifreeze in 3 gallons of solution, then

3 gallons - 100%,

a gallons - 30%,

where a gallons is the amount of pure antifreeze in given solution.

Mathematically,

$\dfrac{3}{a}=\dfrac{100}{30},\\ \\a=\dfrac{3\cdot 30}{100}=0.9\ gallons.$

Now in new solution there will be x+0.9 gallons of pure antefreeze.

x+3 gallons - 100%,

x+0.9 - 65%

$\dfrac{x+3}{x+0.9}=\dfrac{100}{65},\\ \\65(x+3)=100(x+0.9),\\ \\65x+195=100x+90,\\ \\35x=105,\\ \\x=3\ gallons.$

Answer: he should add 3 gallons of pure antifreeze.

8 0

3 years ago

Could someone help me out

AnnyKZ [126]

It is the second one

7 0

3 years ago

Read 2 more answers