All categories

3 years ago

What type of bond forms in iron (2) bromine

Chemistry

1 answer:

jek_recluse [69]3 years ago

8 0

Ionic bond
the metal( iron) gives up the electrons to an non-metal (bromine)

You might be interested in

Fine the mole. 2.41 x 10^24 molecules CO2

vlada-n [284]

Answer:

<h2>4 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{2.41 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.00322...$

We have the final answer as

<h3>4 moles</h3>

Hope this helps you

5 0

3 years ago

Hey, please could someone answer this?

pav-90 [236]

Carbon dioxide is the other product created.

5 0

2 years ago

The relationship between molecular velocities and temperature is a _____ relationship.

elixir [45]

The correct answer that would best complete the given statement above would be option 2. <span>The relationship between molecular velocities and temperature is a direct relationship. In other words, their relationship is directly proportional. Hope that this is the answer that you are looking for. </span>

3 0

3 years ago

Read 2 more answers

Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of t

Slav-nsk [51]

Explanation:

Let us assume that volumes is equal to spheres volume of nucleus.

fm = femto meter = $10^{-15}$

pm = pico meter = $10^{-12}$

Hence, calculate the volume as follows.

V = $\frac{4}{3} \times \pi \times r^{3}$

= $\frac{4}{3} \times 3.14 \times (2.7)^{3}$

= 82.4481 $fm^{3}$ (cubic femtometers)

or, = 82 $fm^{3}$

Now, we will calculate the volume of the atom as follows.

V = $\frac{4}{3} \times \pi \times r^{3}$

= $\frac{4}{3} \times 3.14 \times (70)^{3}$

= 1436758.4 $pm^{3}$ (cubic picometers)

thus, we can conclude that volume of the nucleus is 82 $fm^{3}$ and volume of the atom is 1436758.4 $pm^{3}$ .

7 0

3 years ago

A solid reactant is placed into a beaker of a warm water. The liquid vigorously bubbles as the solid dissolves into the solution

Andrej [43]

Answer:

Fewer bubbles will be produced because of fewer collisions of reactant molecules

Explanation:

As the solid dissolves into the solution after the liquid has been vigorously bubbled, if the temperature of the liquid is reduced a little, what will happen is that fewer bubbles will be produced as a result of lesser amount of collisions occurring between the reactant molecules

3 0

2 years ago

Read 2 more answers