Question

PLEASE HELP MEEEE!!!!​

Answer 1

1. 18 L

2. 20.832 L

Further explanation

Given

Combustion of ethane

Required

Volume of CO₂

Solution

Avogadro's Law :

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

V₁/n₁=V₂/n₂

1. From equation, mol ratio of C₂H₆ : CO₂ ⇒ 2 : 6

so the volume of CO₂ :

= 6/2 x 6 L

= 18 L

2. mol ethane (MW=32 g/mol) :

= mass : MW

= 10 g : 32 g/mol

= 0.31

mol CO₂ :

= 6/2 x 0.31

= 0.93

The volume CO₂(assume at STP) = 20.832 L