Answer: it’s B for edge !
Explanation: took the test
<em>A glass flask of volume 400 cm³ is just filled with mercury at 0°C. How much mercury will overflow when the temperature of the system rises to 80°C.</em>
<em />
The volume of mercury that overflow is 5.376 cm³
<h3>Further explanation</h3>
Given
volume of glass = 400 cm³
Δt=80 °C - 0 °C = 80
Required
overflow volume
Solution
With an increase in the temperature of the substance, objects can expand. This expansion includes volume expansion.
Can be formulated

Find volume expansion of glass and mercury


Overflow :
ΔV mercury - ΔV glass : 5.76-0.384 = 5.376 cm³
Answer:
2.64gram
Explanation:
Molarity, which refers to the molar concentration, is calculated thus:
Molarity = number of moles (n) ÷ volume (L)
According to the question, volume = 100 mL, molarity = 0.240 M.
Since 1L = 1000mL
100 mL = 100/1000
= 0.1L
Hence;
0.240 = n/0.1
n = 0.1 × 0.240
n = 0.024mol
Mole = mass/molar mass
Molar mass of CaCl2 = 40 + 35.5(2)
= 40 + 71
= 111g/mol
mass = molar mass × mole
mass = 110 × 0.024
Mass = 2.64gram
Explanation:
Fe2o3+ 3co ---------. 2fe + 3co2