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igomit [66]
3 years ago
5

Mars has a surface gravity that is only 0.38 (a little over one-third) that of Earth's. Thus, the weight of an object will also

be 0.38 times that of Earth. What is the G.P.E. of a climber who weighs 675 newtons on Earth at the top of 26,000-meter Olympus Mons?
Physics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

Potential energy on surface of Mars is 6669000 J

Explanation:

As we know that the weight of the climber on the surface of Earth is given as 675 N

So weight of the climber on the Mars is given as

W = 0.38 (675)

W = mg = 256.5 N

Now we know that gravitational Potential energy is given as

U = mgH

U = (256.5)(26000)

U = 6669000 J

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wavelength refers to the length of a wave from one peak to the next.the amplitude of a wave Is measured from the peak to the trough

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3 years ago
How much time does it take light to travel from the moon to the earth, a distance of 384000 km?
Natali5045456 [20]

Answer:

1.28second

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6 0
1 year ago
A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en
Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

(c) 4.71 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

-\frac{dU}{dx}=F\\ dU=-Fdx

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

U=\frac{-7}{2}x^{2} + 11x + c

we know that U is equal to 26 J when x is zero, so:

U=\frac{-7}{2}x^{2} + 11x + c

26=\frac{-7}{2}(0)^{2} + 11(0) + c

26=c

Finally, the equation for the potential energy is:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}

Where b is the number beside x and a is the number beside x^{2}, Then, the value of maximum U is:

U(11/7)=\frac{-7}{2}(11/7)^{2} + 11(11/7) + 26

U(11/7)=34.6429J

On the other hand, the negative and positive values of x where the potential energy is equal to zero is calculated as:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

0=\frac{-7}{2}x^{2} + 11x + 26

if we solve this using the quadratic equation, we get:

x =\frac{-11+\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=-1.5747

x =\frac{-11-\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=4.7175

Finally, the negative and positive values of x where the potential energy is equal to zero are -1.5747 and 4.7175 respectively.

3 0
3 years ago
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