Answer:
Percent of Female Workers = 40%
Explanation:
The percentage of the female workers in the given group of workers can be easily found by the following formula:
where,
Total No. of Workers = 1200
No. of Female Workers = Total Workers - No. of Male Workers
No. of Female Workers = 1200 - 720 = 480
Therefore,
<u>Percent of Female Workers = 40%</u>
Answer:
774.8 secs
Explanation:
distance(d)= speed(v)* time(t)
calculate speed:
refractive index = speed of light (c)/ speed of light in medium (v)
1.56 = 3*10^8*v
v=192307692.3 m/s
d = v *t
t = d/v
on substituting values:
t = 774.8 secs
I do a yoga mat that could be different to your answer
-- 'Ca' (Calcium) is an element.
-- The proton has a positive charge.
-- Nuclear fusion results in the synthesis of atoms of new elements.
-- H₂O (water) is a chemical compound.
-- Nuclear fission is a decay of the nucleus.
-- The atomic number of an element is the number of protons
in each atom of it.
-- I suppose you're using the Greek letter <span>η ('eta', not 'nu')
to represent the neutron.
-- I suppose you're using ' e ' to represent the electron.
</span>
Answer:
Explanation:
Given:
Steam Mass rate, ms = 1.5 kg/min
= 1.5 kg/min × 1 min/60 sec
= 0.025 kg/s
Air Mass rate, ma = 100 kg/min
= 100 kg/min × 1 min/60 sec
= 1.67 kg/s
A.
Extracting the specific enthalpy and temperature values from property table of “Saturated water – Pressure table” which corresponds to temperature at 0.07 MPa.
xf, quality = 0.9.
Tsat = 89.9°C
hf = 376.57 kJ/kg
hfg = 2283.38 kJ/kg
Using the equation for specific enthalpy,
hi = hf + (hfg × xf)
= 376.57 + (2283.38 × 0.9)
= 2431.552 kJ/kg
The specific enthalpy of the outlet, h2 = hf
= 376.57 kJ/kg
B.
Rate of enthalpy (heat exchange), Q = mass rate, ms × change in specific enthalpy
= ms × (hi - h2)
= 0.025 × (2431.552 - 376.57)
= 0.025 × 2055.042
= 51.37455 kW
= 51.38 kW.