Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq= =14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5=
14.5 x (0.15 M) x = (CH₃OH)
0.2818 M = (CH₃OH)
The statement correct for the processes are spontaneous reaction have negative Delta H and non-spontaneous reaction has positive Delta H. Hence, option A is correct.
The value of Delta H in the reaction is the change in enthalpy of the reaction. The enthalpy of the reaction determines the reaction to be spontaneous or non-spontaneous.
<h3>What determines spontaneous and non-spontaneous reaction?</h3>
The spontaneous reaction is required with the energy input for the reaction to proceed. The energy is required by the system thus, the value of Delta H is negative.
The non-spontaneous reaction requires with the loss of energy in the formation of the product. The energy released gives the values of Delta H positive.
Thus, the statement correct for the processes are spontaneous reaction have negative Delta H and non-spontaneous reaction has positive Delta H. Hence, option A is correct.
Learn more about Delta H, here:
brainly.com/question/10601562
Answer:
A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :
<u>2.67%</u>
Explanation:
Note : Look at the density of potassium nitrate in water if given in the question.
<u><em>You are calculating </em></u><u><em>weight /Volume</em></u><u><em> not weight/weight % or percent by mass of the solute</em></u>
Here the <u>weight/weight % or percent by mass</u> of the solute is asked : So first convert the<u> VOLUME OF SOLUTION into MASS</u>
Density of potassium nitrate in water KNO3 = 2.11 g/mL
Density = 2.11 g/mL
Volume of solution = 86.4 mL
Mass of Solute = 4.87 g
Mass of Solution = 183.2 g
w/w% of the solute =
w/w%=2.67%
This is false, a compound does not have to contain both cations and anions if ions are present.