Answer:
true
Explanation:
The number of protons, neutrons, and electrons in an atom can be determined from a set of simple rules. The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.
Let the key is free falling, therefore from equation of motion
.
Take initial velocity, u=0, so
.
![h = 0\times t + \frac{1}{2}g t^2= \frac{1}{2}gt^2 \\\ t =\sqrt{\frac{2h}{g} }](https://tex.z-dn.net/?f=h%20%3D%200%5Ctimes%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dg%20t%5E2%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%20%5C%5C%5C%20t%20%3D%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%20%7D)
As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula
![d= v \times t](https://tex.z-dn.net/?f=d%3D%20v%20%5Ctimes%20t)
From above substituting t,
.
Now substituting all the given values and g = 9.8 m/s^2, we get
.
Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.
let the mass of Venus is M then mass of Saturn is 100 M
similarly if the radius of Venus is R then the radius of Saturn is 10 R
now the force of gravity on a man of mass "m" at the surface of Venus is given by
![F_1 = \frac{GMm}{R^2}](https://tex.z-dn.net/?f=F_1%20%3D%20%5Cfrac%7BGMm%7D%7BR%5E2%7D)
now similarly the gravitational force on the man if he is at the surface of Saturn
![F_2 = \frac{G*100M*m}{(10R)^2}](https://tex.z-dn.net/?f=F_2%20%3D%20%5Cfrac%7BG%2A100M%2Am%7D%7B%2810R%29%5E2%7D)
![F_2 = \frac{GMm}{R^2}](https://tex.z-dn.net/?f=F_2%20%3D%20%5Cfrac%7BGMm%7D%7BR%5E2%7D)
so here if we divide the two forces
![\frac{F_1}{F_2} = 1](https://tex.z-dn.net/?f=%5Cfrac%7BF_1%7D%7BF_2%7D%20%3D%201)
so here we can say
F1 = F2
so on both planets the gravitational force will be same
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