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zloy xaker [14]
4 years ago
6

How do electromagnetic waves move through space?

Physics
1 answer:
lesantik [10]4 years ago
4 0

Answer:through a small space through atoms

Explanation:

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Need help with this<br> THANKS TO WHO HELPS &lt;3
nekit [7.7K]

Answer:

because it's north

Explanation:

u if yyggggggggggggggg hgfth

8 0
3 years ago
Read 2 more answers
A dragster with a mass of 700 kg attains a speed of 120 m/s in the quarter mile. Immediately after passing the timing lights, th
Bumek [7]

Answer:

The time taken is 5.55 seconds

Explanation:

Density, p = 1kg/m³

Mass of vehicle, m = 700kg

Initial speed, u = 120m/s

Area of drag chute, A = 7.5 m²

Drag coefficient, Cd = 1.4

Final velocity, v = 20m/s

time taken to decelerate to 20m/s, t = ?

EF = ma

Since the force taken into consideration is the drag force due to the drag chute,

EF = -Fd = -(pACdv²)/2 = ma

a = dv/dt

So the equation can be written as,

-(pACdv²)/2 = m dv/dt

Taking integral of the left hand side with respect to dt and the right with respect to dv with boundaries of 0 to t and u to v,

(pACd)t/2m = (1/v) - (1/u)

t = (2m/pACd) x ( (1/v) - (1/u) ) = f(V)

At V = v

t = (2 x 700)/(1)(7.5)(1.4) x (1/20) - (1/120)

t = 5.55 seconds

6 0
4 years ago
We emphasize performance over participation well before kids' bodies, minds, and interests mature. And we tend to value the chil
Vika [28.1K]

Answer:

Yes.

Explanation:

Yes, we emphasize performance over participation of kids in a competition which causes negative effect on kid's personality. We also prefer those children whose families can afford the fees which is our big failure. We should  emphasize participation over performance and prefer those child who has the ability to win the game instead of those who can afford the fees.

4 0
3 years ago
A driver spotted a police car and he braked from a speed of 100 km/h to a speed of 80 km/h during a displacement of 88 m at a co
jek_recluse [69]

Answer:

Explanation:

100 kph = 27.8 m/s

80 kph = 22.2 m/s

v² = u² + 2as

a = (v² - u²) / 2s

a = (22.2² - 27.8²) / (2(88))

a = -1.578282828...

a = -1.58 m/s²

t negative sign means the acceleration opposes the initial velocity.

t = Δv/a

t = (22.2 - 27.8) / -1.57828

t = 3.52 s

3 0
3 years ago
At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial
elena55 [62]

Answer : The partial pressure of SO_3 is, 67.009 atm

Solution :  Given,

Partial pressure of SO_2 at equilibrium = 30.6 atm

Partial pressure of O_2 at equilibrium = 13.9 atm

Equilibrium constant = K_p=0.345

The given balanced equilibrium reaction is,

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

The expression of K_p will be,

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}

Now put all the values of partial pressure, we get

0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}

p_{SO_3}=67.009atm

Therefore, the partial pressure of SO_3 is, 67.009 atm

6 0
3 years ago
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