The mass of ammonium phosphate that is produced by the reaction between 4.9 g of phosphoric acid and ammonia is 7.45 g (NH₄)₃PO₄
<h2>Further Explanation: </h2><h3>Moles, Atomic mass and Molar mass </h3>
- 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
- Therefore; molar mass is given as grams per mole of a substance
- Hence;
Molar mass = mass of a substance/ Number of moles
g/mol = g /mole
M = m/n; where M is the molar mass, m is the mass and n is the number of moles.
- From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.
That is; Mass = moles x molar mass
To calculate number of moles;
We have; n = m/M
Number of moles = Mass of the substance/ Molar mass
<u>In the question given: </u>
The equation for the reaction between ammonium phosphate and ammonia is given by;
H₃PO₄ + 3NH₃ → (NH₄)₃PO₄
We are required to calculate the mass of ammonium phosphate that is produced from the reaction when 4.9g of phosphoric acid was used.
<h3>Step 1: Moles of phosphoric acid </h3>
Number of moles = Mass of phosphoric acid/ Molar mass
Molar mass of phosphoric acid = 97.994 g/mol
Thus;
Moles = 4.9 g/97.994 g/mol
= 0.050 moles
<h3>
Step 2: Moles of ammonium phosphate </h3>
From the equation ;
H3PO4 + 3 NH3 → (NH4)3PO4
1 mole of phosphoric acid reacts to produce 1 mole of ammonium phosphate
Therefore;
Moles of ammonium phosphate will be;
= 0.050 moles
<h3>
step 3 Mass of ammonium phosphate </h3>
Mass = moles ammonium phosphate × molar mass
Molar mass of ammonium phosphate = 149.09 g/mol
Therefore;
Mass = 0.050 moles × 149.09 g/mol
= 7.45 grams
Hence; The mass of ammonium phosphate that is produced by the reaction between 4.9 g of phosphoric acid and ammonia is 7.45 g (NH₄)₃PO₄
Keywords: Moles, Molar mass, mole ratio
<h3>
Learn more about: </h3>
Level: High school
Subject: Chemistry
Topic: Moles
Sub-topic: Moles, Molar mass
