Question

The heat of solution is found by adding a salt to water in a calorimeter and measuring the temperature change. The specific heat of water is 4.180 Joules per g per ºC. In the calculation of the heat of solution, ignore the contribution to specific heat and mass due to the salt. Assume that these contributions are negligible. The data collected are as follows:
Grams of water in the calorimeter 46.52
Grams of salt 4.5069
Initial temperature of water 22.83 ºC
Final Temperature 18.98 ºC

Calculate the following Heat of the solution of salt.

Answer 1

Answer:

The heat of the solution of salt is 1.66.11 J/g.

Explanation:

Mass of the water = m = 46.52 g

Initial temperature of the water = $T_1=22.83 ^oC$

Final temperature of the water = $T_2=18.98^oC$

The specific heat of water, c = 4.180 J/gºC

Heat associated with water on dissolving salt: q

$Q=mc(T_2-T_1)$

$Q=46.52 g\times 4.180 J/g&oC\times (18.98^oC-22.83 ^oC)$

$Q=-748.65 J$

Negative sign means that heat was lost by water on an addition of a salt.

Heat released on dissolving of salt = -Q = 748.65 J

Mass of salt added = 4.5069 g

Heat of the solution of salt :

= $\frac{-Q}{ 4.5069 g}=\frac{748.65 J}{ 4.5069 g}=1.66.11 J/g$

The heat of the solution of salt is 1.66.11 J/g.