Answer:
a) Aqueous LiBr = Hydrogen Gas
b) Aqueous AgBr = solid Ag
c) Molten LiBr = solid Li
c) Molten AgBr = Solid Ag
Explanation:
a) Aqueous LiBr
This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.
b) Aqueous AgBr
This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.
c) Molten LiBr
In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.
c) Molten AgBr
The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.
Answer:0.45L
Explanation:
molarity=0.15M
Mass=5g
No of moles=mass ➗ molecular mass
Molecular mass of KCL=39.0983x1+35.453x1
Molecular mass of KCL=74.5513
No of moles=5 ➗ 74.5513
No of moles=0.067
Volume in liters=No of moles ➗ molarity
Volume in liters=0.067 ➗ 0.15
Volume in liters=0.45L
→ 
is the net ionic equation for this reaction.
<h3>What is an ionic equation?</h3>
An ionic equation is a synthetic equation where electrolytes are composed as separated particles.
→ is the net ionic equation for this reaction.
A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.
Learn more about ionic equation here:
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Answer:
The balanced equations for those dissociations are:
Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻ (aq)
H₂SO₄ (aq) → 2H⁺(aq) + SO₄⁻²(aq)
Explanation:
As a strong base, the barium hidroxide gives OH⁻ to the solution
As a strong acid, the sulfuric acid gives H⁺ to the solution
Ba(OH)₂, is a strong base so the dissociation is complete.
H₂SO₄ is considerd a strong acid, but only the first deprotonation is strong.
The second proton that is released, has a weak dissociation.
H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)
HSO₄⁻(aq) ⇄ H⁺ (aq) + SO₄⁻² (aq) Ka
