How many moles of SO3 are in 2.4 x 1024 molecules of S03?

Radioactive elements decay via first-order kinetics. consider a certain type of nucleus that has a rate constant of 2.4 × 10–2 h

Leokris [45]

Answer:

37.15 h.

Explanation:

The decay of radioactive elements obeys first-order kinetics.

For first-order reaction: kt = lna/(a-x).

where, k is the rate constant of the reaction (k = 2.4 x 10⁻² h⁻¹).

t is the time of the reaction (t = ??? day).

a is the initial concentration of nuclides (a = 100 %).

(a-x) is the remaining concentration of nuclides (a - x = 100% - 59% = 41.0 %).

∴ kt = lna/(a-x)

(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).

(2.4 x 10⁻² h⁻¹)(t) = 0.8916.

∴ t = (0.8916)/(2.4 x 10⁻² h⁻¹) = 37.15 h.

6 0

3 years ago

B

Gemiola [76]

Answer: 1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water

2. calcium hydroxide + hydrochloric acid = calcium chloride + water

3. lead hydroxide + nitric acid = lead nitrate + water

4. sodium hydroxide + sulfuric acid = sodium sulphate + water

5. potassium hydroxide + citric acid = potassium citrate + water

6. silver hydroxide + hydrochloric acid = silver chloride + water

7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equations are :

1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water

$Mg(OH)_2(aq)+H_2SO_4(aq)\rightarrow MgSO_4(aq)+2H_2O(l)$

2. calcium hydroxide + hydrochloric acid = calcium chloride + water

$Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)$

3. lead hydroxide + nitric acid = lead nitrate + water

$Pb(OH)_2(aq)+2HNO_3(aq)\rightarrow Pb(NO_3)_2(aq)+2H_2O(aq)$

4. sodium hydroxide + sulfuric acid = sodium sulphate + water

$NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)$

5. potassium hydroxide + citric acid = potassium citrate + water

$KOH(aq)+C_6H_8O_7(aq)\rightarrow C_6H_7O_7K(aq)+H_2O(l)$

6. silver hydroxide + hydrochloric acid = silver chloride + water

$AgOH(aq)+HCl(aq)\rightarrow AgCl(s)+H_2O(l)$

7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water

$Al(OH)_3(aq)+H_3PO_4(aq)\rightarrow AlPO_4(aq)+3H_2O(l)$

3 0

3 years ago

Calculate the Molarity of 89.94 g NaCl is dissolved in 1249 mL of solution.

tino4ka555 [31]

Answer:

The molarity of the solution is 1, 23 M.

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

89,94 g ---------x= (89,94 g x 1 mol NaCl)/58, 5 g= 1,54 mol NaCl

1249 ml solution------ 1,54 mol NaCl

1000ml solution------x= (1000ml solutionx 1,54 mol NaCl)/1249 ml solution

x=1,23 mol NaCl---> The solution is 1, 23 molar (1,23 M)

7 0

3 years ago

Use the balanced equation below to answer the question that follows

natta225 [31]

It’s c hdjdkdmnfvdheidk

4 0

3 years ago

Methane has a heat of fusion of 0.84 kJ/mol and a heat of vaporization of 9.2 kJ/mol. Estimate the value for the heat of sublima

Umnica [9.8K]

J BIJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

7 0

2 years ago