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GuDViN [60]
3 years ago
9

How many grams of carbonic acid were produced by the 3.00 g sample of NaHCO

Chemistry
1 answer:
stellarik [79]3 years ago
7 0
I think the given is 3 g sample of NaHCO3. then if it will be reacted with an acid, it will produce H2CO3.
 so the reaction NaHCO3 + HCl --> NaCl + H2CO3

mas of H2CO3 = 3 g NaHCO3 ( 1 mol NaHCO3 / 84 g ) ( 1 mol H2CO3 / 1 mol NaHCO3) ( 62.03 g / 1 mol )
mass of H2CO3 = 2.22 g H2CO3
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A substance has a boiling point of 78 °C. Which of the following is true about the substance? (5 points) a It will also change f
vovangra [49]

Answer: If a substance has a boiling point of 78^{o}C then it is true that it will also change from a gas to a liquid at 78 °C while the gas loses energy.

Explanation:

The temperature at which vapor pressure of a liquid substance becomes equal to the atmospheric pressure is called boiling point of substance.

At the boiling point, liquid phase and vapor phase remains in equilibrium.

This means that as liquid phase changes into vapor phase and also vapor phase changes into liquid phase at the boiling point.

Thus, we can conclude that if a substance has a boiling point of 78^{o}C then it is true that it will also change from a gas to a liquid at 78 °C while the gas loses energy.

6 0
3 years ago
Which of the following is a chemical property of a base?
juin [17]

Answer:

D) forms hydronium ions in water

Explanation:

Texture and conductivity are physical properties which makes answer A and B wrong. Answer C does not refer to a chemical reaction.

4 0
3 years ago
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The speed of sound through air at 20°C is 343 meters per second. The speed of sound through fresh water at 20°C is 1,482 meters
AVprozaik [17]

Answer:

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3 years ago
You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p
Elenna [48]

Answer:

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Explanation:

This is a direct application of the equation for ideal gases.

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Where:

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  • V = volume = 25.2 liter
  • R = Universal constant of gases = 0.08206 atm-liter/K-mol
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Solving for n:

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Substituting:

n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol

8 0
3 years ago
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coldgirl [10]
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when  balancing  equation   the  number  of  atom  of element  should  be the  same  on  each  side  of  equation.
6 0
3 years ago
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