Answer:
6.05g
Explanation:
The reaction is given as;
Ethane + oxygen --> Carbon dioxide + water
2C2H6 + 7O2 --> 4CO2 + 6H2O
From the reaction above;
2 mol of ethane reacts with 7 mol of oxygen.
To proceed, we have to obtain the limiting reagent,
2,71g of ethane;
Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol
3.8g of oxygen;
Number of moles = Mass / molar mass = 3.8 / 16 = 0.2375 mol
If 0.0903 moles of ethane was used, it would require;
2 = 7
0.0903 = x
x = 0.31605 mol of oxygen needed
This means that oxygen is our limiting reagent.
From the reaction,
7 mol of oxygen yields 4 mol of carbon dioxide
0.2375 yields x?
7 = 4
0.2375 = x
x = 0.1357
Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g
Answer:
33.95 grams of NaN3
Explanation:
Number of moles of NaN3 = mass (m)/MW = m/65 mole
I mole of NaN3 requires 22.4L air bag
m/65 mole of NaN3 required 11.7L
22.4m/65 = 11.7
22.4m = 65×11.7
22.4m = 760.5
m = 760.5/22.4 = 33.95grams of NaN3
Explanation:
Below is an attachment containing the solution.
Answer:
a) 1.6
f)7.51
b)3.9
g)9.2
c)3.1
h)41.9
d)1.959
i)0.29
e)5.2
j)1.112
Explanation:
When you are multiplying or dividing the numbers you take the least amount of significant figures and that's how many significant figures your answer will be. Instead of being a super long answer. Hope this helps. Also, sorry it took me a hot minute :)
9 physical
10 physical
11 physical
12 chemical
13 physical
14 chemical
15 physical
If it does not change the chemical makeup which is shown if it makes a change in color, temp, sound, or produces gas, its just a physical change.
