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IRISSAK [1]
4 years ago
14

A copper transmission cable 170 km long and 10.0 cm in diameter carries a current of 100 A .

Physics
1 answer:
Bond [772]4 years ago
8 0

Answer:

a = = 37.2V

b = 13.39MJ

Explanation:

Given that

L = 170 × 10³

r = d/2

= 10cm / 2 = 5 cm

current I = 100A

we are to find the potential drop across the cable

so, we can use ohm’s law

V = IR = I (ρL/A)

ρ = resistivity of the copper

= 1.72 × 10⁻⁸ Ω.m

A = πr²

V = I(ρL/πr²)

= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))

= 37.2V

(b)

Energy (loss) = Pt

Enery (loss) = IVt

 3600s per hour

= (100A)(37.2V)(3600s)

= 13.39MJ

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Explanation:

It is given that,

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(a) Let m is the mass of the ball. The frequency of oscillation of the spring is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

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m=\dfrac{k}{4\pi^2f^2}

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m = 0.0895 kg

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(b) The maximum speed of the ball that is given by :

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v_{max}=A\times 2\pi f

v_{max}=0.075\times 2\pi \times 2.06

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When water has a temperature greater than 100c?
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The animation shows a ball which has been kicked upward at an angle. Run the animation to watch the motion of the ball. Click in
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Answer:

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Explanation:

From the question we are told that

       The maximum height the ball reachs is H_{max} =  42.24 \ m

       The horizontal component of the initial velocity of the ball is v_{ix} = 5.57 \ m/s

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Making the acceleration a_y the subject we have

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