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IRISSAK [1]
3 years ago
14

A copper transmission cable 170 km long and 10.0 cm in diameter carries a current of 100 A .

Physics
1 answer:
Bond [772]3 years ago
8 0

Answer:

a = = 37.2V

b = 13.39MJ

Explanation:

Given that

L = 170 × 10³

r = d/2

= 10cm / 2 = 5 cm

current I = 100A

we are to find the potential drop across the cable

so, we can use ohm’s law

V = IR = I (ρL/A)

ρ = resistivity of the copper

= 1.72 × 10⁻⁸ Ω.m

A = πr²

V = I(ρL/πr²)

= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))

= 37.2V

(b)

Energy (loss) = Pt

Enery (loss) = IVt

 3600s per hour

= (100A)(37.2V)(3600s)

= 13.39MJ

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How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential diffe
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Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV

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In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.

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Answer:

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