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Rom4ik [11]
3 years ago
5

Students perform an experiment in which they drop two eggs with equal mass from a balcony. In the first trial, the egg hits the

ground and breaks. In the second trial, the egg hits a foam cushion and does not break or bounce. what conclusions about impulse can the students make?
Physics
2 answers:
shepuryov [24]3 years ago
8 0

<u> Answer </u>

The impulse on the second trial is smaller is smaller than in the first trial.

<u>Explanation </u>

Impose of a body is that change in momentum during a time interval. If the change of momentum takes longer then, the impulse of a force is less. I a moving object hits a hard surface the rate of change of momentum is very high. e.i in the first trial, the egg breaks because it hits the hard surface(ground).

In the second trial, the foam cushion absorbs the shock and prolongs the time of impact with the egg hence decreasing the impulse.


lapo4ka [179]3 years ago
4 0

Answer: the impact time increases, the impact force decreases.

Explanation:

In the second trial, the impulse is greater.

Impulse = F Δt = Δ P

In the second trial, the egg hits a foam cushion. This increases the time to impact increasing the impulse. In a closed system, the total momentum remains conserved. Thus, the impact time increases, the impact force decreases. Thus, the egg does not break.

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3 years ago
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miss Akunina [59]

Hello!

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Explanation:

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3 0
3 years ago
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8 0
3 years ago
Desde el balcón de un edificio se deja caer una manzana y llega a la planta baja en 5 s. ¿Desde qué piso se dejó caer, si cada p
miv72 [106K]

Answer: 42

Explanation:

I will answer this in English.

We know that the apple needs 5 seconds to reach the ground.

Each floor of the building has a height of 2.88m.

Now, when we drop something, the only force acting on the object is the gravitational one, so the acceleration of the apple is:

a = -g

for the velocity, we integrate the acceleration over time, and as the apple is dropped, we do not have any initial velocity, so we do not have a constant in the integration:

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for the position we integrate again, now we have an initial height H, so the position is:

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i will use g = 9.8m/s^2

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now knowing H, we can divide it by the height of a floor in the building and get the number of the floor.

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