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Rom4ik [11]
3 years ago
5

Students perform an experiment in which they drop two eggs with equal mass from a balcony. In the first trial, the egg hits the

ground and breaks. In the second trial, the egg hits a foam cushion and does not break or bounce. what conclusions about impulse can the students make?
Physics
2 answers:
shepuryov [24]3 years ago
8 0

<u> Answer </u>

The impulse on the second trial is smaller is smaller than in the first trial.

<u>Explanation </u>

Impose of a body is that change in momentum during a time interval. If the change of momentum takes longer then, the impulse of a force is less. I a moving object hits a hard surface the rate of change of momentum is very high. e.i in the first trial, the egg breaks because it hits the hard surface(ground).

In the second trial, the foam cushion absorbs the shock and prolongs the time of impact with the egg hence decreasing the impulse.


lapo4ka [179]3 years ago
4 0

Answer: the impact time increases, the impact force decreases.

Explanation:

In the second trial, the impulse is greater.

Impulse = F Δt = Δ P

In the second trial, the egg hits a foam cushion. This increases the time to impact increasing the impulse. In a closed system, the total momentum remains conserved. Thus, the impact time increases, the impact force decreases. Thus, the egg does not break.

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i.e. u = gt

t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s

So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds

Let d is the maximum distance covered by it.

d=ut-\dfrac{1}{2}gt^2

Putting all values

d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m

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Answer:

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We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

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