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Verizon [17]
4 years ago
6

A discounted amusement park ticket costs $12.95 less than the original price p. write and solve an equation to find the original

price. $44 discounted price
Mathematics
2 answers:
lisov135 [29]4 years ago
7 0
The answer: $56.95

Discounted price is the amount of sum that extracted from the original price when buyers receive some sort of leverage from the seller. In this case, discounted price of the ticket is $44 which was $12.95 less than the original price. Then the original price would be:
$44 + $12.95= $56.95


DanielleElmas [232]4 years ago
3 0

Answer:

Original price of the ticket at the amusement park is $56.95.

Step-by-step explanation:

Original price of the ticket at the amusement park = p

Price of the ticket after discount at the amusement park = D = $44

According to question,discounted amusement park ticket costs $12.95 less than the original price p which can be mathematically can written as:

p-D=\$12.95

On Substituting value of D , we will get the value of p.

p=\$12.95+D=\$12.95+\$44=\$56.95

Original price of the ticket at the amusement park is $56.95.

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We know that

<span>to convert feet to inches we must multiply by 12

</span>4. The distance covered by the cook in Triangle A equals 
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the answer part N 4) is 360 eighteen-inch steps
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5. The distance covered by the cook in Triangle B equals 
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3 0
3 years ago
A random sample of the costs of repair jobs at a large muffler repair shop produces a mean of $127.95. and a standard deviation
lubasha [3.4K]

Answer:

127.95-1.685\frac{24.03}{\sqrt{40}}=121.55    

127.95 +1.685\frac{24.03}{\sqrt{40}}=134.35    

So on this case the 90% confidence interval would be given by (121.55;134.35)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=127.95 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=24.03 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,39)".And we see that t_{\alpha/2}=1.685

Now we have everything in order to replace into formula (1):

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127.95 +1.685\frac{24.03}{\sqrt{40}}=134.35    

So on this case the 90% confidence interval would be given by (121.55;134.35)    

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