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rusak2 [61]
3 years ago
6

Answer the questions below:

Chemistry
2 answers:
Helga [31]3 years ago
8 0
Why do people always send those links like it’s helpful, i’ll help you!
vichka [17]3 years ago
8 0
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Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball a
frosja888 [35]

Answer:

2,7 m

Explanation:

You can solve this doing an energy balance:

m*g*h-\frac{1}{2} *m*v^{2} =41,7[J]

Solving this equation to get h:

\frac{41,7- \frac{1}{2} *m*v^{2} }{m*g}=h

Replacing the values and solving brings to 2,7 m

6 0
3 years ago
Read 2 more answers
Giving brainliest and thanks to best answer <333 :>
valkas [14]

Answer:

C

Explanation:

radiation from the sun first warms the outer atmosphere (trophosphere)

convection(aka just heat moving through gas or liquid) brings the warmth down lower

conduction heats the ground

gl lol :))

7 0
3 years ago
Read 2 more answers
1. How many moles of hydrogen are needed to completely react with two moles of nitrogen?
Arlecino [84]

N2 + 3H2  -->  2NH3

Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.

Explanation:

4 0
2 years ago
The relative atomic mass of Chlorine is 35.45. Calculate the percentage abundance of the two isotopes of Chlorine, 35Cl and 37Cl
nata0808 [166]

Answer:

35Cl = 75.9 %

37Cl = 24.1 %

Explanation:

Step 1: Data given

The relative atomic mass of Chlorine = 35.45 amu

Mass of the isotopes:

35Cl = 34.96885269 amu

37Cl = 36.96590258 amu

Step 2: Calculate percentage abundance

35.45 = x*34.96885269 + y*36.96590258

x+y = 1  x = 1-y

35.45 = (1-y)*34.96885269 + y*36.96590258

35.45 = 34.96885269 - 34.96885269y +36.96590258y

0.48114731 = 1,99704989‬y

y = 0.241 = 24.1 %

35Cl = 34.96885269 amu = 75.9 %

37Cl = 36.96590258 amu = 24.1 %

3 0
3 years ago
How much calcium hypochlorite (65% strength) is needed to make 200 L of 2% hypochlorite solution? (Assume that a 1% solution is
g100num [7]

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

65 x V1 = 2 x 200 L

V1 = 6.15 L

5 0
3 years ago
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