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rusak2 [61]
3 years ago
6

Answer the questions below:

Chemistry
2 answers:
Helga [31]3 years ago
8 0
Why do people always send those links like it’s helpful, i’ll help you!
vichka [17]3 years ago
8 0
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A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t
gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

C_{1} V_{1} = C_{2} V_{2}, where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

C_{2} = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

C_{2} = 288.9/205.0

Performing division on Right Hand Side

C_{2} = 1.4%

Hence, the final concentration is 1.4%.

Learn more about concentration -

brainly.com/question/17206790

#SPJ4

The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

3 0
1 year ago
What is the relationship between radioactive decay and radiometric dating?
Reil [10]

Answer:

Radiometric dating, is called radioactive dating, is a technique used to determine the age of materials such as rocks. It is based on a comparison between the observed abundance of a naturally occurring radioactive isotope and its decay products, using known decay rates.

Explanation:

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6 0
3 years ago
The number of particles of 0.2<br> mole​
tresset_1 [31]

Answer:

1 mole of atoms contains 6.022×1023 atoms. Thus, 0.2 mole of sodium element has 12.044×1022 atoms in it.

Explanation:

8 0
3 years ago
Rats fed normal diet
lana66690 [7]

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Normal diet big and fat and full of poop ready to come out of his bum

if vitamin its the opposite

Explanation:

7 0
4 years ago
What is the calculated molar concentration of the Cl⁻ ions in 0.68 M MnCl2(aq)?
Fudgin [204]
We calculate the molar concentration [Cl⁻]  using stoichiometry. MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.68 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.4 M
The answer to this question is [Cl⁻] = 1.4 M

5 0
3 years ago
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