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Zanzabum
3 years ago
15

A student wants to compare how easily a metal and a plastic spoon of the same temperature can transfer thermal energy. Which of

the following activities should the student perform?
Measure the effort required to bend each spoon.
Place an ice cube on each spoon and record the rate of melting of the cubes.
Place the spoons at room temperature and record the change in temperature of each.
Measure the change in weight of the spoons after placing them in the freezer for a few minutes.
Chemistry
2 answers:
Umnica [9.8K]3 years ago
6 0

Answer: Place an ice cube on each spoon and record the rate of melting of cubes.

We have heard that plastic is an insulator of heat and metal is a conductor of heat. That is why the cooking utensils are made of metal and spoons of plastic.

When ice cube would be placed on the two spoons, the one on metal would melt faster. As metal is a good conductor of heat, the amount of heat transfer would be greater in case of metal spoon and hence, ice would melt faster.


Artist 52 [7]3 years ago
5 0
Measure the effort required to bend each spoon.

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A gas occupies a volume of 85.0 liters at a pressure of 2.24 atm and a temperature of 22.5 degrees celsius. How many moles of ga
White raven [17]

Answer:

n = 7.86 mol

Explanation:

This question can be solved using the ideal gas law of PV = nRT.

Temperature must be in K, so we will convert 22.5C to 295 K ( Kelvin = C + 273).

R is the ideal gas constant of 0.0821.

(2.24atm)(85.0L) = n(0.0821)(295K)

Isolate n to get:

n = (2.24atm)(85.0L)/(0.0821)(295K)

n = 7.86 mol

8 0
3 years ago
13.00 g of hydrazine reacts with
babymother [125]
Hydrazine is a mixed chemical...look up what is in Hydrazine. Then find the chemicals in it. 13.00g of hydrazine can react to anything....water, gas, etc. but it might not be visible.
8 0
3 years ago
Does anyone know the answer to this chemistry question?!? How much HCl is made when 2g of hydrogen reacts? H2+Cl2->2HCl
jonny [76]
<h3>Answer:</h3>

72.19 g HCl

<h3>Explanation:</h3>

We are given the reaction between hydrogen gas and chlorine gas as;

H₂(g) + Cl₂(g) → 2HCl(g)

Mass of hydrogen gas that reacts is 2 g

We are required to determine the amount of HCl produced

<h3>Step 1: Determine the number of moles of H₂ used </h3>

Moles = Mass ÷ molar mass

Molar mass of Hydrogen gas = 2.02 g/mol

Thus;

Moles = 2 g ÷ 2.02 g/mol

          = 0.99 moles

<h3>Step 2: Moles of HCl produced </h3>

From the reaction equation, 1 mole of hydrogen gas reacts to produce 2 moles of HCl

Therefore, the mole ratio of H₂ : HCl = 1 : 2

Thus, moles of HCl = 0.99 moles × 2

                                = 1.98 moles

<h3>Step 3: Mass of HCl produced </h3>

To calculate mass we multiply the number of moles by molar mass

Molar mass of HCl =36.46 g/mol

Therefore;

Mass of HCl = 36.46 g/mol × 1.98 moles

                    = 72.19 g

Thus, the amount of HCl produced during the reaction is 72.19 g

3 0
3 years ago
2KCIO3 -2KCL + 302
Firlakuza [10]

Answer:

a. 6 moles of O₂

b. 4.06×10²⁴ molecules of O₂

c. 3.04 g of KCl

Explanation:

Reaction of decomposition is:

2KClO₃  →  2KCl  +  3O₂

a. See stoichiometry value

2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3

If 2 moles of KClO₃ can decompose to 3 moles of O₂

Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂

b. In this case, the stoichiometry is the same.

Per 2 moles of KClO₃, I produce 2 moles of KCl

Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃

We apply, the last relation:

(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.

How many molecules are in 6.75 moles?

6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂

c. First of all, we convert the mass to moles:

5g . 1mol /122.55g = 0.0408 moles of salt

As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl

We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g

5 0
2 years ago
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ahrayia [7]

Answer:

See below.  

Step-by-step explanation:

Ethers react with HI at high temperature to produce an alky halide and an alcohol.

R-OR' + HI ⟶ R-I + H-OR'

<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.

  1. PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻    Protonation of the ether
  2. PhCH₂-O⁺(H)R  ⟶ PhCH₂⁺ + HOR          Sₙ1 ionization of oxonium ion
  3. PhCH₂⁺ + I⁻       ⟶ PhCH₂-I                     Nucleophilic attack by I⁻  

If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:

ROH +HI ⟶ R-I + H-OH

Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).

The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).

4 0
3 years ago
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