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Zanzabum
3 years ago
15

A student wants to compare how easily a metal and a plastic spoon of the same temperature can transfer thermal energy. Which of

the following activities should the student perform?
Measure the effort required to bend each spoon.
Place an ice cube on each spoon and record the rate of melting of the cubes.
Place the spoons at room temperature and record the change in temperature of each.
Measure the change in weight of the spoons after placing them in the freezer for a few minutes.
Chemistry
2 answers:
Umnica [9.8K]3 years ago
6 0

Answer: Place an ice cube on each spoon and record the rate of melting of cubes.

We have heard that plastic is an insulator of heat and metal is a conductor of heat. That is why the cooking utensils are made of metal and spoons of plastic.

When ice cube would be placed on the two spoons, the one on metal would melt faster. As metal is a good conductor of heat, the amount of heat transfer would be greater in case of metal spoon and hence, ice would melt faster.


Artist 52 [7]3 years ago
5 0
Measure the effort required to bend each spoon.

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What is the hybridization of the central atom in the trichlorostannanide anion?
Mademuasel [1]

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sp²

Explanation:

The trhichlorostannanide anion has molecular formula SnCl₃⁻, Sn is the central atom, which is at the group 14 of the periodic table, so it has 4 valence electrons. It must form 4 bonds to be stable.

In the anion, the tin (Sn) forms 3 bonds, so, it has 1 electron that is isolated. According to the VSEPR theory, the geometry of a molecule depends on the bonded electrons and the lone pairs, because the repulsive force between them will form the angles of the molecule.

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3 years ago
4. What is the bridge that allows you to convert from the given substance to the wanted substance
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6 0
3 years ago
N2H4 + N2O4 --> N2 + H2O
ahrayia [7]

Answer:

  1. The limiting reagent is N2O4
  2. 14,09g

Explanation:

  • First, we adjust the reaction.

2N_{2} H_{4} + N_{2} O_{4} ⇄6N_{2} +  4H_{2}O

  • Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using N_{2} H_{4} to form H_{2}O

               molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4}  }{32,04\frac{g}{mol}  N_{2} H_{4} }

                                           molH_{2} O = 1, 125 mol

Using N_{2} O_{4} to form H_{2} O

              molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4}  }{92\frac{g}{mol}  N_{2} O_{4} }

                                           molH_{2} O = 0,783 mol

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴                          MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}

                                      MassOfH_{2}O = 14,09g

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