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Ira Lisetskai [31]
3 years ago
10

Electron capture equation

Chemistry
1 answer:
Wittaler [7]3 years ago
4 0

Answer :

Electron capture : It is defined as the inner orbital electrons is captured by the nucleus converting a proton into a neutron.

Generally the electron capture equation is represented as,

^A_ZX+^0_{-1}e\rightarrow ^A_{Z-1}Y+x-rays

where,

A = atomic mass number

Z = atomic number

The electron capture equations are :

^{106}_{47}Ag+^0_{-1}e\rightarrow ^{106}_{46}Pd

^{116}_{50}Sn+^0_{-1}e\rightarrow ^{116}_{49}In

^{190}_{78}Pt+^0_{-1}e\rightarrow ^{190}_{77}Ir

^{123}_{53}I+^0_{-1}e\rightarrow ^{123}_{52}Te


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Depends on the thoroughness of that particular experiment. But just in general no, you usually need more than one experiment to verify a hypothesis.
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Dissolving potassium chlorate (KClO3) is even more endothermic than potassium chloride.
zhenek [66]

Answer:

The mass of KClO₃ that will absorb the same heat as 5 g of KCl is 3.424 g

Explanation:

Here we have

Heat of solution of KClO₃ = + 41.38 kJ/mol.

Heat of solution of KCl (+17.24 kJ/mol)

Therefore, 1 mole of KCl absorbs +17.24 kJ during dissolution

Molar mass of KCl = 74.5513 g/mol

Molar mass of KClO₃ = 122.55 g/mol

74.5513 g of KCl absorbs +17.24 kJ during dissolution, therefore, 5 g will absorb

\frac{17.24}{74.5513 } \times 5 \, \, kJ \, or  \, 1.156  \, kJ

Therefore the amount of KClO₃ to be dissolved to absorb 1.156 kJ of energy is given by

122.55 g of KClO₃ absorbs + 41.38 kJ, therefore,

\frac{1.156}{41.38} \times 122.55 \,  g = 3.424 \, g

Therefore the mass of KClO₃ that will absorb the same heat as 5 g of KCl = 3.424 g.

5 0
3 years ago
How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution r
NNADVOKAT [17]
2Al + 3Fe(NO₃)₂ = 3Fe + 2Al(NO₃)₃

m=245 g
w=0.805 (80.5%)
M{Fe(NO₃)₂}=179.857 g/mol
M(Fe)=55.847 g/mol

1. the mass of salt in solution is:
m{Fe(NO₃)₂}=mw

2. the proportion follows from the equation of reaction:
m(Fe)/3M(Fe)=m{Fe(NO₃)₂}/3M{Fe(NO₃)₂}

m(Fe)=M(Fe)m{Fe(NO₃)₂}/M{Fe(NO₃)₂}

m(Fe)=M(Fe)mw/M{Fe(NO₃)₂}

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3 0
3 years ago
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Ethanol is a common laboratory solvent and has a density of 0.789 g/ml. What is the mass, in grams, of 125 ml of ethanol?
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The density of a material is its unique property by which a unknown material can be identified and also the impurity (if present) in a material can be concluded. Mathematically the density can be expressed as-\frac{mass}{volume}. Thus from the mathematical expression we can say that the density is the mass per unit volume of a material. Here the density of ethanol is given 0.789 g/mL. Thus the weight of the 1 mL ethanol is 0.789g. Thus the weight of the 125 mL of ethanol will be (125×0.789) = 98.625 g.

3 0
4 years ago
1. Metallic strontium crystallizes in a face-centered cubic lattice, with one Sr atom per lattice point. If the edge length of t
Zarrin [17]

Answer:

r=215pm

N_{Mn}=20

Explanation:

From the question we are told that:

Edge length of the unit cell l=608pm

a)

Generally the equation for The relationship between edge length and radius is mathematically given by

4r=\sqrt{2a}

Therefore

4r=\sqrt{2*608}

r=\frac{\sqrt{2*608}}{4}

r=215pm

b)

From the question we are told that:

Density \rho=7.297

Edge length of l=630.0 pm=>630*10^-{10}

Therefore Volume  is given as

V=l^3

V=630*10^-{10}^3

V=2.50047*10^{−22}

Generally the equation for Mass is mathematically given by

m=Volume*density

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m=1.83*10^{-21}g

Therefore Molarity is given as

n=\frac{M}{Molar M}

n=\frac{1.83*10^{-21}g}{55}

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Finally The atoms in a unit cell is

N_{Mn}=Moles*Avogadro\ constant

N_{Mn}=3.32*10^{-23}*6.023*10^{23}

N_{Mn}=20

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