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fiasKO [112]
3 years ago
13

The ____________ ___________ is the outer part of the atom?

Chemistry
1 answer:
abruzzese [7]3 years ago
3 0
Possibly electron shells, t<span>he </span>electrons<span> in the outermost occupied </span>shell<span> (or </span>shells<span>) determine the chemical properties of the atom..</span>
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What kind of solid is crystalline boron
Ulleksa [173]

Answer:

It is a network solid, a lattice of many covalent bonds (like diamond, except that it is black rather than transparent).

Explanation:

7 0
3 years ago
EQUILIBRIUM Two moles of compound P were placed in a vessel. The vessel was heated and compound P was partially decomposed to pr
Reika [66]

As given:

Initial moles of P taken = 2 mol

the products are R and Q

at equilibrium the moles of

R = x

total moles =  2 + x/2

Let us check for each reaction

A) P <-> 2Q+R

Here if x moles of P gets decomposed it will give 2x moles of Q and x moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = 2x

moles of R = x

Total moles = (2-x) + 2x + x = 2 +2x

B) 2P <-> 2Q+R

Here x moles of P will give x moles of Q and x/2 moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = x

moles of R = x/2

Total moles = (2-x) + x + x/2 = 2 + x/2

C) 2P <-> Q+R

Here x moles of P will give x/2 moles of Q and x/2 moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = x /2

moles of R = x/2

Total moles = (2-x) + x + x = 2

D) 2P <-> Q+2R

Here x moles of P will give x/2 moles of Q and x moles of R

So at equilibrium

moles of P left = 2-x

moles of Q = x/2

moles of R = x

Total moles = (2-x) + x/2 + x = 2 + x/2

3 0
3 years ago
How does natural selection change the traits of living things over long periods of time? *
WARRIOR [948]
The answer for this one is C . Organisms are always changing traits
8 0
3 years ago
Read 2 more answers
32.5 g to fluid ounces
uysha [10]
It’s 4160 fluid ounces
8 0
3 years ago
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
bulgar [2K]

Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052

\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

4 0
3 years ago
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