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fiasKO [112]
3 years ago
13

The ____________ ___________ is the outer part of the atom?

Chemistry
1 answer:
abruzzese [7]3 years ago
3 0
Possibly electron shells, t<span>he </span>electrons<span> in the outermost occupied </span>shell<span> (or </span>shells<span>) determine the chemical properties of the atom..</span>
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When copper crystallizes, it forms face-centered cubic cells. The unit cell edge length is 361.5 pm. Calculate the density of co
Olegator [25]

Density of copper can be calculated using the following formula:

d=\frac{m}{V}

Here, m is mass and V is volume, thus, to calculate density first calculate mass and volume of copper.

In FCC, number of atoms in a unit cell are 4, atomic mass of Cu is 63.546 g/mol and number of atoms in 1 mole is 6.023\times 10^{23}.

Mass of Cu will be:

m=4 atoms\times \frac{1 mol}{6.023\times 10^{23}}\times \frac{63.546 g}{mol}=4.22\times 10^{-22}g

Now, volume can be calculate as:

V=a^{3}

Here, a is edge length.

First convert edge length from pm to cm

1pm=10^{-10}cm

Thus,

361.5 pm=3.615\times 10^{-8}cm

Putting the value,

V=(3.615\times 10^{-8} cm)^{3}=4.72\times 10^{-23} cm^{3}

Now, from mass and volume density can be calculated as follows:

d=\frac{m}{V}=\frac{4.22\times 10^{-22}g}{4.72\times 10^{-23} cm^{3}}=8.932 g/cm^{3}

Therefore, density of copper will be 8.932 g/cm^{3}.

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